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NEW QUESTION: 1
あなたはアプリケーションをテストしています。 このアプリケーションには、CalculateInterestおよびLogLineという名前のメソッドが含まれています。 CalculateInterest（）メソッドは、ローンの利子を計算します。 LogLine（）メソッドは、診断メッセージをコンソールウィンドウに送信します。
あなたには次の要件があります。
* CalculateInterest（）メソッドは、すべてのビルド構成に対して実行する必要があります。
* LogLine（）メソッドは、デバッグビルドでのみ呼び出される必要があります。
メソッドが正しく実行されるようにする必要があります。
関連コードをどのように完成させるべきですか？ （回答するには、適切なコードセグメントを回答エリアの正しい場所にドラッグします。各コードセグメントは、1回、複数回、またはまったく使用されないことがあります。）

Answer:
Explanation:

Explanation

When the C# compiler encounters an #if directive, followed eventually by an #endif directive, it will compile the code between the directives only if the specified symbol is defined. Unlike C and C++, you cannot assign a numeric value to a symbol; the #if statement in C# is Boolean and only tests whether the symbol has been defined or not. For example,
#define DEBUG
#if DEBUG
Console.WriteLine("Debug version");
#endif
Reference: http://stackoverflow.com/questions/2104099/c-sharp-if-then-directives-for-debug-vs-release

NEW QUESTION: 2
Refer to the exhibit.

The company uses EIGRP as the routing protocol. What path will packets take from a host on
192.168.10.192/26 network to a host on the LAN attached to router R1?
R3# show ip route Gateway of last resort is not set 192 168.20.0/24 is variably subnetted, 6 subnets, 2 masks D 192.168.20.64/26 [90/2195456] via 192.168.20.9, 00:03:31, Serial0/0 D 192.168.20.0/30 [90/2681856] via 192.168.20.9, 00:03:31, Serial0/0 C 192.168.20.4/30 is directly connected, Serial0/1 C 192.168.20.8/30 is directly connected, Serial0/0 C 192.168.20.192/26 is directly connected, FastEthernet0/0 D 192.168.20.128/26 [90/2195456] via 192.168.20.5,00:03:31, Serial0/1
A. The path of the packets will be both R3 to R2 to R1 and R3 to R1
B. The path of the packets will be R3 to R1 to R2
C. The path of the packets will be R3 to R1
D. The path of the packets will be R3 to R2 to R1
Answer: C
Explanation:
http://www.orbitco-ccna-pastquestions.com/CCNA---EIGRP-Common-Question.php
Looking at the output display above, the LAN attached to router R1 belongs to 192.168.20.64/26 subnet and learned this network via 192.168.20.9 which will be an IP address in 192.168.20.8/30 sub-network. This means that packets destined for
192.168.20.64 will be routed from R3 to R1.

NEW QUESTION: 3
Discovery, recording, collection, and preservation are part of what process related to the gathering of evidence?
A. Admissibility of evidence
B. The chain of evidence
C. The evidence life cycle
D. Relevance of evidence
Answer: C
Explanation:
The correct answer is The evidence life cycle. The evidence life cycle covers the evidence gathering and application process.
* Answer "Admissibility of evidence" refers to certain requirements
that evidence must meet to be admissible in court.
* Answer "The chain of evidence" the chain of evidence, is comprised of steps that must be followed to protect the evidence.
* Relevance of evidence is one of the requirements of evidence admissibility.

NEW QUESTION: 4
What is the effect of the send-lifetime local 23:59:00 31 December 31 2013 infinite command?
A. It configures the device to begin accepting the authentication key from other devices at 00:00:00 local time on
January 1, 2014 and continue accepting the key indefinitely.
B. It configures the device to generate a new authentication key and transmit it to other devices at 23:59:00 local time
on December 31, 2013.
C. It configures the device to begin transmitting the authentication key to other devices at 23:59:00 local time on
December 31, 2013 and continue using the key indefinitely.
D. It configures the device to begin accepting the authentication key from other devices immediately and stop
accepting the key at 23:59:00 local time on December 31, 2013.
E. It configures the device to begin accepting the authentication key from other devices at 23:59:00 local time on
December 31, 2013 and continue accepting the key indefinitely.
F. It configures the device to begin transmitting the authentication key to other devices at 00:00:00 local time on
January 1, 2014 and continue using the key indefinitely.
Answer: C