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NEW QUESTION: 1
A. Cable management
B. Network switch
C. KVM
D. Fiber cables
E. Rail kit
F. UPS
Answer: D,E
NEW QUESTION: 2
Assume a client's traffic is being processed only by a NAT; no SNAT or virtual server processing takes place. Also assume that the NAT definition specifies a NAT address and an origin address while all other settings are left at their defaults. If the origin server were to initiate traffic via the BIG-IP, what changes, if any, would take place when the BIG-IP processes such packets.
A. The BIG-IP would drop the request since the traffic didn arrive destined to the NAT address.
B. The source address would be changed to the NAT address and destination address would be left unchanged.
C. The source address would not change, but the destination address would be changed to the NAT address.
D. The source address would not change, but the destination address would be changed to a self-IP of the BIG-IP.
Answer: B
NEW QUESTION: 3
Refer to the exhibit. The network is converged.After link-state advertisements are received from Router_A, what information will Router_E contain in its routing table for the subnets 208.149.23.64 and
208.149.23.96?
A. 208.149.23.64[110/13]via190.173.23.10,00:00:07, Serial1/0208.149.23.96[110/13]via
190.173.23.10,
00:00:16, Serial1/0 208.149.23.96[110/13] via 190.173.23.10, 00:00:16, FastEthemet0/0
B. 208.149.23.64[110/3]via190.172.23.10,00:00:07, Serial1/0208.149.23.96[110/3]via190.173.23.10,
00:00:16, Serial1/0
C. 208.149.23.64[110/1]via190.172.23.10,00:00:07, Serial1/0208.149.23.96[110/3]via190.173.23.10,
00:00:16, FastEthemet0/0
D. 208.149.23.64[110/13]via190.173.23.10,00:00:07, FastEthemet0/0208.149.23.96[110/13]via
190.173.23.10, 00:00:16, FastEthemet0/0
Answer: D
Explanation:
Explanation/Reference:
Explanation:
Router_E learns two subnets subnets 208.149.23.64 and 208.149.23.96 via Router_A through FastEthernet interface. The interface cost is calculated with the formula 108 / Bandwidth. For FastEthernet it is 108 / 100 Mbps = 108 / 100,000,000 = 1. Therefore, the cost is 12 (learned from Router_A) + 1 = 13 for both subnets -> The cost through T1 link is much higher than through T3 link (T1 cost = 108 / 1.544 Mbps = 64; T3 cost
108 / 45 Mbps = 2) so surely OSPF will choose the path through T3 link -> Router_E will choose the path from Router_A through FastEthernet0/0, not Serial1/0. In fact, we can quickly eliminate answers B, C and D because they contain at least one subnet learned from Serial1/0 -> they are surely incorrect.
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