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NEW QUESTION: 1
When an EIGRP topology change is detected, what is the correct order of events when there is a FS?
A. The neighbor adjacency is deleted.
Routes enter the Active state and the feasible route is used.
DUAL is notified.
Remove all topology entries learned from that neighbor.
B. DUAL is notified.
Remove all topology entries learned from that neighbor.
The neighbor adjacency is deleted.
Routes enter the Active state and the feasible route is used.
C. DUAL is notified.
The neighbor adjacency is deleted.
Remove all topology entries learned from that neighbor.
The feasible route is used.
D. The neighbor adjacency is deleted.
The feasible route is used.
DUAL is notified.
Remove all topology entries learned from that neighbor.
Answer: C
Explanation:
Explanation/Reference:
Explanation:
If a packet is not received before the expiration of the hold time, the neighbor adjacency is deleted, and all topology table entries learned from that neighbor are removed, as if the neighbor had sent an update stating that all the routes are unreachable. If the neighbor is a successor for any destination networks, those networks are removed from the routing table, and alternative paths, if available, are computed. This lets the routes quickly reconverge if an alternative feasible route is available.

NEW QUESTION: 2
Ann, a small business owner, would like to implement wireless networking for her business but wants to be sure the wireless is ONLY accessible from within her business' premises. Which of the following would BEST accomplish this?
A. Using unidirectional antennas and reducing radio power levels appropriately
B. Assigning DHCP addresses that expire after a shorter period of time
C. Disabling SSID broadcast to ensure that only employees know the SSID
D. Using omni-directional antennas and reducing radio power levels appropriately
Answer: A

NEW QUESTION: 3

A. Repeatable
B. Serializable
C. ReadCommitted
D. ReadUncommitted
Answer: C

NEW QUESTION: 4
The router address 192.168.1.250 is the default gateway for both the Web Server 2 and Host 1. What is the correct subnet mask for this network?

A. 255.255.255.250
B. 255.255.255.252
C. 255.255.255.0
D. 255.255.255.128
Answer: C
Explanation:
1.Based on the information provided in the exhibit, we know that the IP address of the interface Fa0/0 is 192.168.1.250/24, that is to say the subnet mask is 255.255.255.0??
2.When configuring the correct IP address and not wasting IP address, the network of
192.168.1.0 needs to contain the following three IP addresses of interfaces: R1(fa 0/0) : 192.168.1.250 Host1: 192.168.1.106/24 Web server 2: 192.168.1.10/24 The correct mask is 255.255.255.0.