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NEW QUESTION: 1
Which Cisco Meeting Server component is used for interworking different communication protocols?
A. Recorder
B. Web Bridge
C. 323 gateway
D. XMPP Server
Answer: C

NEW QUESTION: 2

Refer to the exhibit. R1 is unable to establish an OSPF neighbor relationship with R3. What are two possible reasons for this problem? (Choose two.)
A. The hello and dead interval timers are not set to the same values on R1 and R3.
B. All of the routers need to be configured for backbone Area 1.
C. R1 and R3 are configured in different areas.
D. A static route has been configured from R1 to R3 and prevents the neighbor adjacency from being established.
E. R1 and R2 are the DR and BDR, so OSPF will not establish neighbor adjacency with R3.
F. EIGRP is also configured on these routers with a lower administrative distance.
Answer: A,C

NEW QUESTION: 3
Exhibit

Examine the data in the EMPLOYEES and DEPARTMENTS tables.
You want to retrieve all employees' last names, along with their manager's last names and their department names. Which query would you use?
A. SELECT e.last_name, m.last_name, department_name
FROM employees e
LEFT OUTER JOIN employees m on ( e.manager_id = m.employee_id)
RIGT OUTER JOIN departments d ON (e.department_id = d.department_id);
B. SELECT e.last_name, m.last_name, department_name
FROM employees e
RIGT OUTER JOIN employees m on ( e.manager_id = m.employee_id)
LEFT OUTER JOIN departments d ON (e.department_id = d.department_id);
C. SELECT e.last_name, m.last_name, department_name
FROM employees e
RIGHT OUTER JOIN employees m on ( e.manager_id = m.employee_id)
RIGHT OUTER JOIN departments d ON (e.department_id = d.department_id)
D. SELECT last_name, manager_id, department_name
FROM employees e
JOIN departments d ON (e.department_id = d.department_id) ;
E. SELECT last_name, manager_id, department_name
FROM employees e
FULL OUTER JOIN departments d ON (e.department_id = d.department_id);
F. SELECT e.last_name, m.last_name, department_name
FROM employees e
LEFT OUTER JOIN employees m on ( e.managaer_id = m.employee_id)
LEFT OUTER JOIN departments d ON (e.department_id = d.department_id);
Answer: F