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NEW QUESTION: 1
A client served by an OceanStor 9000 requires that if one channel fails, data can be transmitted over another channel without service interruption. To address this requirement, a necessary condition is that the client support SMB 3.0.
A. FALSE
B. TRUE
Answer: B

NEW QUESTION: 2
A system has three components and all three components need to be operational for 24 hours; Monday to Friday. During a particular week, failure of component 2 occurred as follows:
Monday = 6 PM to 9 PM
Tuesday = 8 AM to 10 AM
Wednesday = No failure
Thursday = 8 PM to 9 PM
Friday = No failure
Saturday = 5 AM to 8 AM
Sunday = 6 PM to 9 PM
What is the mean time between failures on component 2?
A. 30 Hours
B. 40 Hours
C. 38 Hours
D. 42 Hours
Answer: C

NEW QUESTION: 3
Which method is NOT supported to provision an Aruba thin AP?
A. Telnet directly to AP
B. SSH to the AP's controller
C. Web interface to the AP's controller
D. Console to AP
Answer: A
Explanation:
Topic 2, Volume B

NEW QUESTION: 4
Note: This question is part of a series of questions that use the same or similar answer choices. An answer choice may be correct for more than one question in the series. Each question is independent of the other questions in this series. Information and details provided in a question apply to that question.
You have a database for a banking system. The database has two tables named tblDepositAcct and tblLoanAcct that store deposit and loan accounts, respectively. Both tables contain the following columns:

You need to determine the total number of deposit and loan accounts.
Which Transact-SQL statement should you run?
A. SELECT COUNT (DISTINCT D.CustNo)
FROM tblDepositAcct D, tblLoanAcct L
WHERE D.CustNo = L.CustNo
B. SELECT COUNT (DISTINCT COALESCE(D.CustNo, L.CustNo))
FROM tblDepositAcct D
FULL JOIN tblLoanAcct L ON D.CustNo =L.CustNo
WHERE D.CustNo IS NULL OR L.CustNo IS NULL
C. SELECT COUNT(*)
FROM (SELECT CustNo
FROM tblDepositAcct
UNION
SELECT CustNo
FROM tblLoanAcct) R
D. SELECT COUNT(*)
FROM (SELECT CustNo
FROMtblDepositAcct
UNION ALL
SELECT CustNo
FROM tblLoanAcct) R
E. SELECT COUNT(*)
FROM (SELECT AcctNo
FROM tblDepositAcct
INTERSECT
SELECT AcctNo
FROM tblLoanAcct) R
F. SELECT COUNT(DISTINCT L.CustNo)
FROM tblDepositAcct D
RIGHT JOIN tblLoanAcct L ON D.CustNo =L.CustNo
WHERE D.CustNo IS NULL
G. SELECT COUNT(*)
FROM tblDepositAcct D
FULL JOIN tblLoanAcct L ON D.CustNo = L.CustNo
H. SELECT COUNT(*)
FROM (SELECT CustNo
FROM tblDepositAcct
EXCEPT
SELECT CustNo
FROM tblLoanAcct) R
Answer: D
Explanation:
Explanation/Reference:
Explanation:
Would list the customers with duplicates, which would equal the number of accounts.
Incorrect Answers:
A: INTERSECT returns distinct rows that are output by both the left and right input queries operator.
B: Would list the customers without duplicates.
D: Number of customers.
F: EXCEPT returns distinct rows from the left input query that aren't output by the right input query.
References:
https://msdn.microsoft.com/en-us/library/ms180026.aspx