CAS-004 Practice Questions

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NEW QUESTION: 1
A major study on private security was prepared by the:
A. American Society for Industrial Security
B. Private Security Task Force of the National Advisory Committee on Criminal Justice Standards and
Goals
C. Harvard Symposium in Private Security
D. Brookings Institute
E. International Association of Chiefs of Police
Answer: B

NEW QUESTION: 2
What SPAN configuration is required to enable on a switch?
A. LLDP must be enable in an interface.
B. Disable VTP pruning on trunk links
C. A monitor VLAN is created for the SPAN traffic.
D. Configure a source and destination port
Answer: D

NEW QUESTION: 3
Which statement is true when you provision an Autonomous Database using the cloning method?
A. After an Autonomous database is created using a clone, the network access option can be changed.
B. When cloning an Autonomous Database, Oracle Machine Learning workspaces, projects, and notebooks of the source database are cloned to the new database.
C. A clone database source can be a running database instance.
D. A clone database source can be from a point-in-time backup that is less than 2 hours old.
Answer: B

NEW QUESTION: 4
What happens when you attempt to compile and run the following code?
# include <vector>
# include <string>
# include <iostream>
# include <algorithm>
# include <ctype.h>
using namespace std;
template<typename T>class B { T val;
public:
B(T v):val(v){}
T getV() const {return val;} };
template<class T>ostream & operator <<(ostream & out, const B<T> & v) { out<<v.getV(); return out;}
template<class T>struct Out {
ostream & out;
Out(ostream & o): out(o){}
void operator() (const T & val ) { out<<val<<" "; } };
string tolower(const string & s) {
string tmp(s);
for(unsigned i = 0; i< tmp.size(); ++i){
tmp[i] = tolower(tmp[i]); }
return tmp; }
bool Less(const B<string> &a, const B<string> &b) {
return tolower(a.getV())<tolower(b.getV()); }
int main() {
string t[]={"aaa","bbb","Aaa", "Bbb","aAa","bBb","aaA","bbB"};
vector<B<string> > v1; v1.assign(t, t+8);
stable_sort(v1.begin(), v1.end(), Less);
for_each(v1.begin(), v1.end(), Out<B<string> >(cout));cout<<endl;
return 0;
}
Program outputs:
A. Aaa aaa aAa aaA bbb Bbb bbB bBb
B. Aaa aaa aAa aaA bbb Bbb bBb bbB
C. aaa Aaa aAa aaA bbb Bbb bBb bbB
D. the exact output is impossible to determine
Answer: C