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NEW QUESTION: 1
IBM Trvoli Netcool / OMNIbus（Netcool / OMNIbus）V8.1でのSSL証明書とキーの移行に関して正しい説明はどれですか。
A. Netcool / OMNIbus V7.2（およびそれ以前）で作成された証明書は、V8.1と互換性のない形式で保存されます。
B. 古いomni.kdbデータベースではなく、別のパスワードを使用する必要があります。
C. 必要なSSL証明書とキーは、自動プロセスであるため、Netcool / OMNIbusV8.1インストールで手動で作成または生成しないでください。
D. キーデータベースはNCHOME / etc / security / SSLディレクトリに保存されます。 Netcool / OMNIbusV8.1キーデータベースファイルの名前はnetcool.kdbです。
Answer: D

NEW QUESTION: 2
The sales management team of Universal Containers has noticed that opportunities are taking longer to close.
Historically, it has taken 30 days for a new opportunity to be moved to closed/won. Recently, this time period has increased to 45 days. What analytics tool can the sales management team leverage to help determine the cause? Choose 2 answers
A. Dashboard of Month-over-month trend of lead conversions
B. Dashboard of opportunity stage duration
C. Report on the discount approval time for quotes
D. Report on campaign return on investment (ROI)
Answer: B,C

NEW QUESTION: 3
Which four statements are correct regarding IS-IS operations? (Choose four.)
A. By default, Level 1 routers within an IS-IS area do not carry any routing information external to the area to which they belong. They use a default route to exit the area.
B. IS-IS supports "route leaking" in which selected Level 2 routes can be advertised by a Level 1/Level 2 router into Level 1.
C. With IS-IS, an individual router is in only one area, and the border between areas is on the link that connects two routers that are in different areas.
D. The IS-IS backbone is a contiguous collection of Level 1 capable routers, each of which can be in a different area.
E. Summarization should be configured on the Level 2 routers, which injects the Level 2 routes into Level
1.
F. Cisco IOS XR Software supports multitopology for IPv6 IS-IS unless single topology is explicitly configured in IPv6 address-family configuration mode.
Answer: A,B,C,F
Explanation:
Explanation/Reference:
Explanation:

NEW QUESTION: 4
質問をドラッグアンドドロップ
IPv4ネットワークサブネットを左側から右側の正しい使用可能なホスト範囲にドラッグアンドドロップします

Answer:
Explanation:

Explanation:
This subnet question requires us to grasp how to subnet very well. To quickly find out the subnet range, we have to find out the increment and the network address of each subnet. Let's take an example with the subnet 172.28.228.144/18:
From the /18 (= 1100 0000 in the 3rd octet), we find out the increment is 64. Therefore the network address of this subnet must be the greatest multiple of the increment but not greater than the value in the 3rd octet (228). We can find out the 3rd octet of the network address is 192 (because 192 = 64 * 3 and 192 < 228) -> The network address is 172.28.192.0. So the first usable host should be 172.28.192.1 and it matches with the 5th answer on the right. In this case we don't need to calculate the broadcast address because we found the correct answer.
Let's take another example with subnet 172.28.228.144/23 -> The increment is 2 (as /23 = 1111
1110 in 3rd octet) -> The 3rd octet of the network address is 228 (because 228 is the multiply of 2 and equal to the 3rd octet) -> The network address is 172.28.228.0 -> The first usable host is
172.28.228.1. It is not necessary but if we want to find out the broadcast address of this subnet, we can find out the next network address, which is 172.28.(228 + the increment number).0 or
172.28.230.0 then reduce 1 bit -> 172.28.229.255 is the broadcast address of our subnet.
Therefore the last usable host is 172.28.229.254.