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NEW QUESTION: 1
The advantage of sending messages using steganographic techniques, as opposed to utilizing encryption, is that:
A. reliability of the data is higher in transit.
B. required key sizes are smaller.
C. the existence of messages is unknown.
D. traffic cannot be sniffed.
Answer: C
Explanation:
Explanation/Reference:
Explanation:
The existence of messages is hidden when using steganography. This is the greatest risk. Keys are relevant for encryption and not for steganography. Sniffing of steganographic traffic is also possible. Option D is not relevant.

NEW QUESTION: 2
You EPM Report is enabled to send data and comments. You type in a revenue value and a comment in the
EPM report and save the data. Where is the data stored? (1)
A. The revenue data in a infocube and the comment in a DataStore Object
B. Both the revenue value and the comment in a Infocube
C. Both the revenue value and the comment in a DataStore Object
D. The revenue data in a infocube and the comment in another database table
Answer: D

NEW QUESTION: 3
Sie verwalten eine Microsoft SQL Server 2014-Datenbank mit dem Namen ContosoDb. Die Tabellen sind wie im Exponat angegeben definiert. (Klicken Sie auf die Schaltfläche "Ausstellen".)

Sie müssen Zeilen aus der Orders-Tabelle für die Customers-Zeile mit dem CustomerId-Wert 1 im folgenden XML-Format anzeigen.

Welche Transact-SQL-Abfrage sollten Sie verwenden?
A. SELECT OrderId, OrderDate, Amount, Name, CountryFROM OrdersINNER JOIN CustomersON Orders.CustomerId = Customers.CustomerIdWHERE Customers.CustomerId = 1FOR XML RAW, ELEMENTS
B. SELECT Name, Land, Orderld, OrderDate, AmountFROM OrdersINNER JOIN CustomersON Orders.CustomerId = Customers.CustomerIdWHERE Customers.CustomerId = 1FOR XML AUTO, ELEMENTS
C. SELECT OrderId, OrderDate, Amount, Name, CountryFROM OrdersINNER JOIN CustomersON Orders.CustomerId = Customers.CustomerIdWHERE Customers.CustomerId = 1FOR XML AUTO
D. SELECT Name, Land, Crderld, OrderDate, AmountFROM OrdersINNER JOIN CustomersON Orders.CustomerId = Customers.CustomerIdWHERE Customers.CustomerId = FÜR XML AUTO, ELEMENTS
E. SELECT OrderId, OrderDate, Amount, Name, CountryFROM OrdersINNER JOIN CustomersON Orders.CustomerId * Customers.CustomerIdWHERE Customers.CustomerId = 1FOR XML AUTO, ELEMENTS
F. SELECT Name AS `Customers / Name ', CountryAS` Customers / Country', OrderId, OrderDate, AmountFROM OrdersINNER JOIN CustomersON Orders.CustomerId = Customers.CustomerIdWHERE Customers.CustomerId = 1FOR XML PATH (`Customers '
G. SELECT Name AS `@Name ', CountryAS` @Country', OrderId, OrderDate, AmountFROM OrdersINNER JOIN CustomersON Orders.CustomerId = Customers.CustomerIdWHERE Customers.CustomerId = 1FOR XML PATH
H. SELECT OrderId, OrderDate, Amount, Name, CountryFROM OrdersINNER JOIN CustomersON Orders.CustomerId = Customers-CustomerIdWHERE Customers.CustomerId = 1FOR XML RAW
Answer: B