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NEW QUESTION: 1
Which option describes how you add software conference bridges to Cisco Unified Communications Manager?
A. By installing DSP to a Cisco Unified CM server.
B. By reassigning other media resources to conference resources.
C. By adding a Cisco Unified CM server to the cluster.
D. By adding a software conference bridge using Conference Bridge Configuration.
Answer: C

NEW QUESTION: 2
A technician is preparing to activate the needed services in Cisco Unified Communications Manager to integrate with an IM and Presence server. Which four services must be enabled? (Choose four.)
A. Cisco Directory Sync
B. Cisco Unified Communications Manager
C. Cisco Extended Functions
D. Cisco TFTP
E. Cisco AXL Web Service
F. Cisco CTI Manager
G. Cisco Intercluster Lookup Service
H. Cisco Messaging Interface
Answer: B,D,E,F

NEW QUESTION: 3
企業はマルチアカウント戦略を実施しています。ただし、管理チームは、DNSなどのサービスが過度に複雑になる可能性があるという懸念を表明しています。会社には、異なるアカウントの仮想プライベートクラウド（VPC）間でプライベートDNSを共有できるソリューションが必要です。会社は合計で約50のアカウントを持ちます。
どのソリューションが最も複雑なDNSアーキテクチャを作成し、各VPCがすべてのAWSリソースを解決できるようにしますか？
A. VPC属性enableDnsHostnamesおよびenableDnsSupportをすべてのVPCで「false」に設定します。プライベート仮想インターフェイスを使用してAWS Direct Connect接続を作成します。仮想インターフェイスでUDPおよびTCPポート53を許可します。オンプレミスDNSサーバーを使用して、AWS上の各VPCのIPアドレスを解決します。
B. すべてのアカウントのVPC間にVPCピア接続を作成します。 VPC属性enableDnsHostnamesおよびenableDnsSupportを各VPCに対して「true」に設定します。 VPCごとにAmazon Route 53プライベートゾーンを作成します。ドメインとサブドメインのリソースレコードセットを作成します。
各VPCのホストゾーンを他のVPCとプログラムで関連付けます。
C. 中央アカウントで共有サービスVPCを作成し、共有サービスVPCから他のアカウントの各VPCへのVPCピアリング接続を作成します。 Amazon Route 53内で、共有サービスVPCにプライベートホストゾーンを作成し、ドメインとサブドメインのリソースレコードセットを作成します。
プログラムで他のVPCをホストゾーンに関連付けます。
D. 中央アカウントで共有サービスVPCを作成します。他のアカウントのVPCから共有サービスVPCへのVPCピアリング接続を作成します。ドメインおよびサブドメインのリソースレコードセットを使用して、共有サービスVPCにAmazon Route 53プライベートホストゾーンを作成します。 VPCピアリング接続でUDPおよびTCPポート53を許可します。
Answer: C

NEW QUESTION: 4
Refer to the exhibit.

The network is converged.After link-state advertisements are received from Router_A, what information will Router_E contain in its routing table for the subnets 208.149.23.64 and 208.149.23.96?
A. 208.149.23.64[110/1] via 190.172.23.10, 00:00:07, Serial1/0 208.149.23.96[110/3] via 190.173.23.10, 00:00:16, FastEthemet0/0
B. 208.149.23.64[110/13] via 190.173.23.10, 00:00:07, FastEthemet0/0 208.149.23.96[110/13] via 190.173.23.10, 00:00:16, FastEthemet0/0
C. 208.149.23.64[110/3] via 190.172.23.10, 00:00:07, Serial1/0 208.149.23.96[110/3] via 190.173.23.10, 00:00:16, Serial1/0
D. 208.149.23.64[110/13] via 190.173.23.10, 00:00:07, Serial1/0 208.149.23.96[110/13] via 190.173.23.10, 00:00:16, Serial1/0 208.149.23.96[110/13] via 190.173.23.10, 00:00:16, FastEthemet0/0
Answer: B
Explanation:
Explanation Router_E learns two subnets subnets 208.149.23.64 and 208.149.23.96 via Router_A through FastEthernet interface. The interface cost is calculated with the formula 108 / Bandwidth. For FastEthernet it is 108 / 100 Mbps = 108 / 100,000,000 = 1. Therefore the cost is 12 (learned from Router_A) + 1 = 13 for both subnets -> The cost through T1 link is much higher than through T3 link (T1 cost = 108 / 1.544 Mbps = 64; T3 cost = 108 / 45 Mbps = 2) so surely OSPF will choose the path through T3 link -> Router_E will choose the path from Router_A through FastEthernet0/0, not Serial1/0. In fact, we can quickly eliminate answers B, C and D because they contain at least one subnet learned from Serial1/0 -> they are surely incorrect.