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NEW QUESTION: 1
Refer to the exhibit.

An administrator created a backplane stack with the plug-and-play method, and did not alter the default backplane stacking settings. Later, two backplane stacking links failed, as shown in the exhibit.
What happens to the backplane stack after the failures?
A. The standby becomes the commander of its fragment. Both fragments remain active and operate at both Layer 2 and Layer 3.
B. The fragment that contains the commander operates at Layer 2 and Layer 3, and the other fragment operates at Layer 2 only.
C. The fragment that contains the commander remains active, and the fragment with the standby member is disabled.
D. The standby becomes the commander of its fragment, which remains active. The fragment with the commander becomes inactive.
Answer: A

NEW QUESTION: 2
Hintergrund
Sie verwalten eine Umgebung mit mehreren Mandanten, die in Microsoft Azure gehostet wird. Alle Änderungen an der Datenbank werden in eine Vorlagendatenbank übertragen, die als Microsoft Azure SQL-Datenbank mit dem Namen contosoTempiate gespeichert ist und auf dem virtuellen SQL Server mit dem Namen SQL1 gespeichert ist. Sie haben auch einen virtuellen SQL Server namens SQL2.
Sie stellen eine Azure SQL-Datenbankinstanz mit dem Namen DB1 bereit. Es wurden keine Azure-Firewallregeln erstellt.
Sie planen, die folgenden Datenbanken in einem elastischen Pool bereitzustellen: EDB2, EDB3, EDB4, EDB5 und EDB6. Alle Datenbanken im Pool weisen dieselbe Spitzenverwendungsdauer auf.
Sie migrieren eine SQL Server-Instanz mit dem Namen srvi auf eine virtuelle Maschine der Azure DS-13-Serie. Die VM verfügt über zwei Premium-Festplatten, die als Speicherpool zugeordnet sind.
Sie planen, eine neue Azure SQL-Datenbank mit dem Namen DB7 bereitzustellen, um eine Anwendung für Ihre Personalabteilung zu unterstützen.
Sie sollten verhindern, dass Benutzer, die keine Administratoren sind, vertrauliche Daten anzeigen, die in DB7 gespeichert sind. Sie sollten dies tun, ohne Codeänderungen an den verschiedenen Anwendungen vorzunehmen, die die Daten lesen.
Unternehmensziele für die Datenmaskierung erfordern die folgenden Formate:

Sie müssen für jeden Feldtyp eine dynamische Datenmaskierung implementieren.
Wie soll die Transact-SQL-Anweisung ausgefüllt werden? Ziehen Sie zum Beantworten die entsprechenden Transact-SQL-Segmente an die richtigen Positionen. Jedes Transact-SQL-Segment kann einmal, mehrmals oder gar nicht verwendet werden. Möglicherweise müssen Sie die geteilte Leiste zwischen den Fenstern ziehen oder einen Bildlauf durchführen, um den Inhalt anzuzeigen.

Answer:
Explanation:

Erläuterung

Box 1: ADD MASKED WITH (FUNCTION = 'email ()')
Bei der E-Mail-Maskierungsmethode werden der erste Buchstabe einer E-Mail-Adresse und das Konstantensuffix ".com" in Form einer E-Mail-Adresse angezeigt. . [email protected].
Dieses Standardverhalten ist das, was wir wollen.
Beispieldefinitionssyntax: Email varchar (100) MASKED WITH (FUNCTION = 'email ()') NULL Feld 2: ADD MASKED WITH (FUNCTION = 'partiell (2, "XX-XX-XX", 2) Die benutzerdefinierte Maskierungsmethode welche macht den ersten und letzten Buchstaben sichtbar und fügt in der Mitte eine benutzerdefinierte Füllzeichenfolge hinzu. Syntax: Präfix, [Füllzeichen], Suffix
https://docs.microsoft.com/de-de/sql/relational-databases/security/dynamic-data-masking?view=sql-server-2017

NEW QUESTION: 3
User smith on station2 is trying to chat with the remote user bob on station1 using the talk command, smith receives an error message as shown below:
[smith@station2 ~]$talk [email protected]
[No connection yet]
[ Error on read from talk daemon: Connection refused ]
[smith@station2 ~]$
What can the root user do to resolve the issue? (Choose two.)
A. let smith retry talk after restarting the xinetd service with ntalk enabled on both systems
B. let smith retry the talk request with UDP port 518 open on both systems
C. let smith retry talk after restarting the network service with the UDP port 517 blocked on both systems
D. let smith retry talk by reading from STDIN and sending to bob
E. let smith retry talk after changing the group of talk command to tty
Answer: A,B