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NEW QUESTION: 1
Your database supports a mixed workload. In an application, multiple complex queries with functions and expressions are executing. You want to analyze the queries that are currently cached in the library cache to receive recommendations about the usage of indexes and materialized views.
What should you do to achieve this? (Choose the best answer.)
A. Create an STS for the queries cached in the library cache and submit it as an input to SQL Performance Analyzer.
B. Capture the workload in an STS and submit to SQL Tuning Advisor for recommendations.
C. Create an STS for the queries cached in the library cache and submit it as an input to SQL Tuning Advisor.
D. Create an STS for the queries cached in the library cache and submit it as an input to SQL Access Advisor.
Answer: A

NEW QUESTION: 2
You create a table that has the StudentCode, SubjectCode, and Marks columns to record mid-year marks for students. The table has marks obtained by 50 students for various subjects.
You need to ensure that the following requirements are met:
Students must be ranked based on their average marks.

If one or more students have the same average, the same rank must be given to these students.

Consecutive ranks must be skipped when the same rank is assigned.

Which Transact-SQL query should you use?
A. SELECT StudentCode AS Code,Marks AS Value FROM (
SELECT StudentCode, Marks AS Marks,
RANXO OVER(PARTITION BY StudentCode ORDER BY Marks DESC) AS Rank
FROM StudentMarks) tmp
WHERE Rank = 1
B. SELECT StudentCode as Code,
RANK() OVER(ORDER BY AVG (Marks) DESC) AS Value
FROM StudentMarks
GROUP BY StudentCode
C. SELECT StudentCode as Code,
NTILE(2) OVER(ORDER BY AVG (Marks) DESC) AS Value
FROM StudentMarks
GROUP BY StudentCode
D. SELECT StudentCode AS Code,Marks AS Value FROM (
SELECT StudentCode, Marks AS Marks,
RANK() OVER(PARTITION BY StudentCode ORDER BY Marks ASC) AS Rank
FROM StudentMarks) tmp
WHERE Rank = 1
E. SELECT Id, Name, Marks,
DENSE_RANK() OVER(ORDER BY Marks DESC) AS Rank
FROM StudentMarks
F. SELECT StudentCode AS Code,Marks AS Value FROM (
SELECT StudentCode, Marks AS Marks,
RANK() OVER(PARTITION BY SubjectCode ORDER BY Marks DESC) AS Rank
FROM StudentMarks) tmp
WHERE Rank = 1
G. SELECT StudentCode AS Code,Marks AS Value FROM (
SELECT StudentCode, Marks AS Marks,
RANK() OVER(PARTITION BY SubjectCode ORDER BY Marks ASC) AS Rank
FROM StudentMarks) tmp
WHERE Rank = 1
H. SELECT StudentCode as Code,
DENSE_RANK() OVER(ORDER BY AVG (Marks) DESC) AS Value
FROM StudentMarks
GROUP BY StudentCode
Answer: B
Explanation:
Explanation/Reference:
Reference: http://msdn.microsoft.com/en-us/library/ms189798.aspx

NEW QUESTION: 3

A. Option D
B. Option A
C. Option C
D. Option B
Answer: A,C

NEW QUESTION: 4

A. Option D
B. Option A
C. Option C
D. Option B
Answer: C