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NEW QUESTION: 1
Which QoS component alters a packet to change the way that traffic is treated in the network?
A. Shaping
B. Policing
C. Classification
D. Marking
Answer: D
Explanation:
Explanation
QoS Packet Marking refers to changing a field within a packet either at Layer 2 (802.1Q/p CoS, MPLS EXP) or Layer 3 (IP Precedence, DSCP and/or IP ECN).
Reference: https://www.cisco.com/c/en/us/td/docs/ios-xml/ios/qos_mqc/configuration/xe-16/qosmqc- xe-16-book/qos-mrkg.html

NEW QUESTION: 2
Which statement best links a customer problem to a solution capability for the entire BSM solution?
A. Problem: too much lost productivity and time chasing network issues Solution: Network Automation (NA)
B. Problem: determining which events matter and which are just "noise" Solution: Operations Manager (i)
C. Problem: the inability to capture the end-user experience Solution: Real user Monitor (RUM)
D. Problem: the inability to capture and consolidate infrastructure and application events in real time Solution: HP Run-time Service Model (RTSM)
Answer: D

NEW QUESTION: 3
A company has an Active Directory Domain Services (AD DS) domain. All client computers run Windows 10 Enterprise and are joined to the domain.
Corporate police prohibits homegroups on the corporate network.
You need to ensure that client computer network adapter settings do not support joining a homegroup.
What should you do?
A. Enable IPv4.
B. Disable IPv6.
C. Disable IPv4.
D. Enable IPv6.
Answer: B
Explanation:
https://h30434.www3.hp.com/t5/Notebook-Wireless-and-Networking/Windows-10-can-t-set- up-a-homegroup-on-this-computer/td-p/5581558

NEW QUESTION: 4
What happens when you attempt to compile and run the following code?
# include <vector>
# include <iostream>
# include <algorithm>
using namespace std;
class B { int val;
public:
B(int v):val(v){}
int getV() const {return val;} bool operator < (const B & v) const { return val<v.val;} }; ostream & operator <<(ostream & out, const B & v) { out<<v.getV(); return out;} template<class T>struct Out {
ostream & out;
Out(ostream & o): out(o){}
void operator() (const T & val ) { out<<val<<" "; } };
int main() {
B t1[]={3,2,4,1,5};
int t2[]={5,6,8,2,1};
vector<B> v1(10,0);
sort(t1, t1+5);
sort(t2, t2+5);
set_union(t1,t1+5,t2,t2+5,v1.begin());
for_each(v1.begin(), v1.end(), Out<B>(cout));cout<<endl;
return 0;
}
Program outputs:
A. 1 2 3 4 5 6 8 2 1 0
B. 1 1 2 2 3 4 5 5 6 8
C. compilation error
D. 1 2 3 4 5 6 8 0 0 0
E. 3 2 4 1 5 6 8 2 1 0
Answer: C