C_KYMD_01 Practice Questions

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NEW QUESTION: 1
Which statement is true about the Density badge? (Choose the best answer.)
A. The Density badge considers memory only
B. The Density badge considers CPU, memory and storage only
C. The Density badge considers CPU only
D. The Density badge considers CPU and memory only
Answer: D
Explanation:
Explanation/Reference:
Reference https://blogs.vmware.com/management/2015/05/understanding-density-badge-vrealize- operations-tech-tips-14.html

NEW QUESTION: 2
You are designing the data access layer (DAL) for an application that uses Microsoft SQL
Server 2008, Microsoft ADO.NET, and Microsoft Visual Studio 2010.
Conflicts are occurring in the SQL Server database due to concurrent updates.
You need to design a database locking strategy that meets the following requirements:
What should you do?
A. Use pessimistic locking. Retry the failing update operation in the DBConcurrencyException exception handler until it succeeds.
B. Use pessimistic locking. Terminate the update when a DBConcurrencyException occurs.
C. Use optimistic locking. In the DBConcurrencyException exception handler, display the data of both original and updated records to the user. Allow the user to resolve the conflicts.
D. Use optimistic locking. Terminate the update when a DBConcurrencyException occurs.
Answer: C

NEW QUESTION: 3
Which statement about the feasibility condition in EIGRP is true?
A. The EIGRP peer that advertises the prefix to the router is closer to the destination than the router.
B. The EIGRP peer that advertises the prefix to the router has multiple paths to the destination.
C. The prefix is reachable via an EIGRP peer that is in the routing domain of the router.
D. The EIGRP peer that advertises the prefix cannot be used as a next hop to reach the destination.
Answer: A
Explanation:
The advertised metric from an EIGRP neighbor (peer) to the local router is called Advertised Distance (or reported distance) while the metric from the local router to that network is called Feasible Distance. For example, R1 advertises network 10.10.10.0/24 with a metric of 20 to R2. For R2, this is the advertised distance. R2 calculates the feasible distance by adding the metric from the advertised router (R1) to itself. So in this case the feasible distance to network 10.10.10.0/24 is 20 + 50 = 70.

Before a router can be considered a feasible successor, it must pass the feasibility condition rule.
In short, the feasibility condition says that if we learn about a prefix from a neighbor, the advertised
distance from that neighbor to the destination must be lower than our feasible distance to that
same destination.
Therefore we see the Advertised Distance always smaller than the Feasible Distance to satisfy the
feasibility condition.