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NEW QUESTION: 1
ある会社に、1つのアベイラビリティーゾーンのEC2インスタンスで実行されているアプリケーションがあります。 SysOps管理者は、アプリケーションを高可用性にすることを任務としています。管理者が実行中のEC2インスタンスから起動設定を作成しました。管理者はロードバランサーも適切に設定しました。
アプリケーションの可用性を高めるために、管理者は次にどのようなステップを実行する必要がありますか？
A. 最小サイズ2、希望容量2、最大2の3つ以上のアベイラビリティーゾーンにわたって起動設定を使用して、Auto Scalingグループを作成します。
B. 最小サイズ2、希望容量2、最大サイズ2の3つ以上のリージョンで起動設定を使用してAuto Scalingグループを作成します。
C. 最小サイズ1、希望容量1、最大サイズ1の2つ以上のアベイラビリティーゾーンにわたって起動設定を使用して、Auto Scalingグループを作成します。
D. 最小サイズ1、希望容量1、最大サイズ1の2つ以上のリージョンで起動設定を使用してAuto Scalingグループを作成します。
Answer: C

NEW QUESTION: 2
SIMULATION

Answer:
Explanation:
Router>enable
Router#config terminal
Router(config)#hostname Apopka
2) Enable-secret password (cisco10):
Apopka(config)#enable secret cisco10
3) Set the console password to RouterPass:
Apopka(config)#line console 0
Apopka(config-line)#password RouterPass
Apopka(config-line)#login
Apopka(config-line)#exit
4) Set the Telnet password to scan90:
Apopka(config)#line vty 0 4
Apopka(config-line)#password scan90
Apopka(config-line)#login
Apopka(config-line)#exit
5) Configure Ethernet interface (on the right) of router Apopka:
The subnet mask of the Ethernet network 209.165.201.0 is 27. From this subnet mask, we can find out the increment
by converting it into binary form, that is /27 = 1111 1111.1111 1111.1111 1111.1110 0000. Pay more attention to the
last bit 1 because it tells us the increment, using the formula:
Increment = 2place of the last bit 1 (starts counting from 0,from right to left), in this case increment = 25 = 32.
Therefore:
Increment: 32
Network address: 209.165.201.0
Broadcast address: 209.165.201.31 (because 209.165.201.32 is the second subnetwork, so the previous IP -
209.165.201.31 - is the broadcast address of the first subnet).
-> The second assignable host address of this subnetwork is 209.165.201.2/27
Assign the second assignable host address to Fa0/0 interface of Apopka router:
Apopka(config)#interface Fa0/0
Apopka(config-if)#ip address 209.165.201.2 255.255.255.224
Apopka(config-if)#no shutdown
Apopka(config-if)#exit
6) Configure Serial interface (on the left) of router Apopka:
Using the same method to find out the increment of the Serial network:
Serial network 192.0.2.128/28:
Increment: 16 (/28 = 1111 1111.1111 1111.1111 1111.1111 0000)
Network address: 192.0.2.128 (because 8 * 16 = 128 so 192.0.2.128 is also the network address of this subnet)
Broadcast address: 192.0.2.143
-> The last assignable host address in this subnet is 192.0.2.142/28.
Assign the last assignable host address to S0/0/0 interface of Apopka router:
Apopka(config)#interface S0/0/0 (or use interface S0/0 if not successful)
Apopka(config-if)#ip address 192.0.2.142 255.255.255.240
Apopka(config-if)#no shutdown
Apopka(config-if)#exit
7) Configure RIP v2 routing protocol:
Apopka(config)#router rip
Apopka(config-router)#version 2
Apopka(config-router)#network 209.165.201.0
Apopka(config-router)#network 192.0.2.128
Apopka(config-router)#end
Save the configuration:
Apopka#copy running-config startup-config
Finally, you should use the ping command to verify all are working properly!

NEW QUESTION: 3
You discover during your initial assessment that a new client's skill level in every exercise is high with no
corrections needed. She has exercised with a personal trainer for more than three years. At which level of
learning is the client?
A. Reciprocal stage
B. Autonomous stage
C. Cognitive stage
D. Associative stage
Answer: B