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NEW QUESTION: 1
Drag and Drop Question
You develop a web app that uses the tier D1 app service plan by using the Web Apps feature of Microsoft Azure App Service.
Spikes in traffic have caused increases in page load times.
You need to ensure that the web app automatically scales when CPU load is about 85 percent and minimize costs.
Which four actions should you perform in sequence? To answer, move the appropriate actions from the list of actions to the answer area and arrange them in the correct order.
NOTE: Each correct selection is worth one point.

Answer:
Explanation:

Explanation:
Step 1: Configure the web app to the Standard App Service Tier
The Standard tier supports auto-scaling, and we should minimize the cost.
Step 2: Enable autoscaling on the web app
First enable autoscale
Step 3: Add a scale rule
Step 4: Add a Scale condidation
References:
https://docs.microsoft.com/en-us/azure/monitoring-and-diagnostics/monitoring-autoscale-get- started
https://azure.microsoft.com/en-us/pricing/details/app-service/plans/

NEW QUESTION: 2
Which two statements describe the benefits provided by firewall services deployed by NSX? (Choose two.)
A. Firewall services deployed using a software appliance will provide east-west traffic filtering and security.
B. Firewall services providing edge security services uses a distributed kernel module.
C. Firewall services providing edge security services uses a virtual appliance and is centrally managed.
D. Firewall services deployed using a distributed kernel module will provide east-west traffic filtering and security.
Answer: C,D

NEW QUESTION: 3
Given the network diagram.

Which address would successfully summarize only the networks seen?
A. 192.168.16.0/21
B. 192.168.12.0/20
C. 192.168.8.0/21
D. These networks cannot be summarized.
E. 192.168.8.0/20
F. 192.168.0.0/24
Answer: C
Explanation:
let's suppose it is a /20 then we would have addresses from 192.168.0.1 to 192.168.15.255 Now let's suppose it is a /21 then we would have addresses from 192.168.8.1 to
192.168.15.255
So both summaries encompass the networks we want to summarize but the second one is the most restrictive one as it only encompasses the networks we were asked to summarize and not others so it is the correct summary.
In fact just count the number of subnets which is 8 and find the exponent of 2 which is 8, that gives you 3 and to find out the summary mask just do /24 - 3 = /21.
if you make it in binary you'll find out the answer too:
the interesting octet is 3rd one so let's convert in binary.
8 0000 1000
9 0000 1001
1 0 0000 1010
1 1 0000 1011
1 2 0000 1100
1 3 0000 1101
1 4 0000 1110
1 5 0000 1111
I've bolded the bits in common there are 5 so 16+5=21 which is mask and address is
1 92.168.8.0

NEW QUESTION: 4
What type of BGP sessions does router R2 need to establish in order to reach networks 192.168.1.0/27 and 192.168.5.0/27?
A. An iBGP peering session with router R1, and an eBGP peering session with router R4
B. An eBGP peering session with router R1, and iBGP peering sessions with routers R3 and R4
C. iBGP peering sessions with routers R1 and R5
D. eBGP peering sessions with routers R1, R3 and R4
Answer: B