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NEW QUESTION: 1
Sie haben ein virtuelles Azure-Netzwerk mit dem Namen VNet1, das über ein Standort-zu-Standort-VPN eine Verbindung zu Ihrem lokalen Netzwerk herstellt. VMet1 enthält ein Subnetz namens Subnetz1.
Subnetz1 ist einer Netzwerksicherheitsgruppe (Network Security Group, NSG) mit dem Namen NSG1 zugeordnet. Subnetz1 enthält einen grundlegenden internen Lastenausgleich namens ILB1. ILB1 verfügt über drei virtuelle Azure-Maschinen im Back-End-Pool.
Sie müssen Daten über die IP-Adressen sammeln, die mit ILB1 verbunden sind. Sie müssen in der Lage sein, über das Azure-Portal interaktive Abfragen für die erfassten Daten auszuführen.
Was tun? Wählen Sie zum Beantworten die entsprechenden Optionen im Antwortbereich aus.
HINWEIS: Jede richtige Auswahl ist einen Punkt wert.

Answer:
Explanation:

Erläuterung

Kasten 1: Ein Azure Log Analytics-Arbeitsbereich
Im Azure-Portal können Sie einen Log Analytics-Arbeitsbereich einrichten. Hierbei handelt es sich um eine eindeutige Log Analytics-Umgebung mit einem eigenen Datenrepository, Datenquellen und Lösungen. Box 2: ILB1-Referenzen:
https://docs.microsoft.com/en-us/azure/log-analytics/log-analytics-quick-create-workspace
https://docs.microsoft.com/en-us/azure/load-balancer/load-balancer-standard-diagnostics

NEW QUESTION: 2
A VNX customer is making a decision on the type of splitters to use with RecoverPoint/SE 3.x in their environment. The environment has a small number of Microsoft Windows hosts with several LUNs greater than 2 TB. After making a decision to use host splitters, the customer realizes this is not a viable solution.
Why would the customer reach this conclusion?
A. VNX splitters must be used if there are under 20 hosts
B. Host splitters are only best for a large number of hosts
C. VNX splitters must be used when the LUN size is greater than 2 TB
D. VNX splitters must be used if there are only Windows hosts
Answer: C

NEW QUESTION: 3
Note: This question is part of a series of questions that use the same scenario. For your convenience, the scenario is repeated in each question. Each question presents a different goal and answer choices, but the text of the scenario is exactly the same in each question in this series.
You query a database that includes two tables: Project and Task. The Project table includes the following columns:


You need to identify the owner of each task by using the following rules:
- Return each task's owner if the task has an owner.
- If a task has no owner, but is associated with a project that has an owner, return the project's owner.
- Return the value -1 for all other cases.
How should you complete the Transact-SQL statement? To answer, select the appropriate Transact-SQL segments in the answer area.

Answer:
Explanation:

Explanation
Box 1: COALESCE
COALESCE evaluates the arguments in order and returns the current value of the first expression that initially does not evaluate to NULL.
Box 2: T.UserID, p.UserID, -1
- Return each task's owner if the task has an owner.
- If a task has no owner, but is associated with a project that has an owner, return the project's owner.
- Return the value -1 for all other cases.
Box 3: LEFT JOIN
The LEFT JOIN keyword returns all rows from the right table (table2), with the matching rows in the left table (table1). The result is NULL in the left side when there is no match. Here the right side could be NULL as the projectID of the task could be NULL.
References:
https://msdn.microsoft.com/en-us/library/ms190349.aspx
http://www.w3schools.com/Sql/sql_join_right.asp

NEW QUESTION: 4



A. 208.149.23.64[110/13] via 190.173.23.10, 00:00:07, Serial1/0 208.149.23.96[110/13] via 190.173.23.10, 00:00:16, Serial1/0 208.149.23.96[110/13] via 190.173.23.10, 00:00:16, FastEthemet0/0
B. 208.149.23.64[110/3] via 190.172.23.10, 00:00:07, Serial1/0 208.149.23.96[110/3] via 190.173.23.10, 00:00:16, Serial1/0
C. 208.149.23.64[110/1] via 190.172.23.10, 00:00:07, Serial1/0 208.149.23.96[110/3] via 190.173.23.10, 00:00:16, FastEthemet0/0
D. 208.149.23.64[110/13] via 190.173.23.10, 00:00:07, FastEthemet0/0 208.149.23.96[110/13] via 190.173.23.10, 00:00:16, FastEthemet0/0
Answer: D
Explanation:
Explanation
Router_E learns two subnets subnets 208.149.23.64 and 208.149.23.96 via Router_A through FastEthernet interface. The interface cost is calculated with the formula 108 / Bandwidth. For FastEthernet it is 108 / 100 Mbps = 108 / 100,000,000 = 1. Therefore the cost is 12 (learned from Router_A) + 1 = 13 for both subnets -> The cost through T1 link is much higher than through T3 link (T1 cost = 108 / 1.544 Mbps = 64; T3 cost = 108
/ 45 Mbps = 2) so surely OSPF will choose the path through T3 link -> Router_E will choose the path from Router_A through FastEthernet0/0, not Serial1/0.
In fact, we can quickly eliminate answers B, C and D because they contain at least one subnet learned from Serial1/0 -> they are surely incorrect.