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NEW QUESTION: 1
An RSA SecurID tokencode is unique for each successful authentication because
A. a token periodically calculates a new code.
B. the Node Secret is updated after each authentication.
C. the user continuously changes their secret PIN.
D. the Authenticaiton Manager instance clock is set to Universal Coordinated Time.
Answer: A

NEW QUESTION: 2
Welcher Befehl muss eingegeben werden, wenn ein Gerät als NTP-Server konfiguriert ist?
A. NTP-Peer
B. NTP-Server
C. NTP-Authentifizierung
D. NTP-Master
Verwenden Sie den Befehl ntp master [stratum], um ein Cisco-Gerät als autorisierenden NTP-Server zu konfigurieren. Verwenden Sie den Befehl ntp server <IP-Adresse>, um ein Cisco-Gerät als NTP-Client zu konfigurieren. Zum Beispiel: Router (config) #ntp server 192.168.1.1. Dieser Befehl weist den Router an, 192.168.1.1 für die Zeit abzufragen.
Answer: D

NEW QUESTION: 3
You are working for a company that designs mobile applications. They maintain a server where player records
are assigned to their different games. The tracking system is new and in development.
The application uses Entity Framework to connect to an Azure Database. The database holds a Player table
and Game table.
When adding a player, the code should insert a new player record, and add a relationship between an existing
game record and the new player record.
The application will call CreatePlayerWithGame with the correct gameIdand the playerId to start the process.
(Line numbers are included for reference only.)

For each of the following statements, select Yes if the statement is true. Otherwise, select No.
NOTE: Each correct selection is worth one point.

Answer:
Explanation:

Explanation

Many-to-many relationships without an entity class to represent the join table are not yet supported. However,
you can represent a many-to-many relationship by including an entity class for the join table and mapping two
separate one-to-many relationships.
protected override void OnModelCreating(ModelBuilder modelBuilder)
{
modelBuilder.Entity<PostTag>()
HasKey(t => new { t.PostId, t.TagId });
modelBuilder.Entity<PostTag>()
HasOne(pt => pt.Post)
WithMany(p => p.PostTags)
HasForeignKey(pt => pt.PostId);
modelBuilder.Entity<PostTag>()
HasOne(pt => pt.Tag)
WithMany(t => t.PostTags)
HasForeignKey(pt => pt.TagId);
}
}


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