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NEW QUESTION: 1
Scenario: A call center has deployed Access Gateway Enterprise to provide its employees with access to work resources from home. Due to the number of available licenses, only selected employees should access the environment remotely based on their user account information. How could the engineer configure access to meet the needs of this scenario?
A. Configure a Pre-authentication Policy.
B. Configure an Authentication Policy using Client based expressions.
C. Configure an Authentication Server using a search filter.
D. Add the selected employee accounts to the Local Authentication policy.
Answer: C

NEW QUESTION: 2
What are two reasons why a company would choose to use VMware Server 1 .x instead of using ESX Server 3.x? (Choose two.)
A. The company wants to utilize NIC teaming for network path failover and loadbalancing.
B. The company wants to virtualize a large number of physical machines running legacyoperating systems in their datacenter.
C. ESX Server 3.x does not support the storage hardware the company wants to use.
D. VMware Server 1 .x allows users to run the same number of virtual machines per CPUcore as ESX Server 3.x does at the same performance levels at a lower cost.
E. VMware Server 1.x is a lower-cost solution for departmental virtualization projects.
Answer: C,E

NEW QUESTION: 3
You create a table that has the StudentCode, SubjectCode, and Marks columns to record mid-year marks for students. The table has marks obtained by 50 students for various subjects.
You need to retrieve the students who scored the highest marks for each subject along with the marks.
Which Transact-SQL query should you use?
A. SELECT StudentCode AS Code, Marks AS Value FROM (
SELECT StudentCode, Marks AS Marks,
RANK() OVER(PARTITION BY SubjectCode ORDER BY Marks ASC) AS Rank
FROM StudentMarks) tmp
WHERE Rank = 1
B. SELECT StudentCode AS Code, Marks AS Value FROM (
SELECT StudentCode, Marks AS Marks,
RANK() OVER(PARTITION BY SubjectCode ORDER BY Marks DESC) AS Rank
FROM StudentMarks) tmp
WHERE Rank = 1
C. SELECT StudentCode as Code, DENSE_RANK() OVER(ORDER BY AVG(Marks) DESC) AS Value FROM StudentMarks
GROUP BY StudentCode
D. SELECT StudentCode as Code, NTILE(2) OVER(ORDER BY AVG(Marks) DESC) AS Value FROM StudentMarks GROUP BY StudentCode
E. SELECT StudentCode as Code, RANK() OVER(ORDER BY AVG(Marks) DESC) AS Value FROM StudentMarks GROUP BY StudentCode
F. SELECT StudentCode AS Code, Marks AS Value FROM (
SELECT StudentCode, Marks AS Marks,
RANXO OVER(PARTITION BY StudentCode ORDER BY Marks DESC) AS Rank
FROM StudentMarks) tmp
WHERE Rank = 1
G. SELECT StudentCode AS Code, Marks AS Value FROM (
SELECT StudentCode, Marks AS Marks,
RANK() OVER(PARTITION BY StudentCode ORDER BY Marks ASC) AS Rank
FROM StudentMarks) tmp
WHERE Rank = 1
H. SELECT Id, Name, Marks, DENSE_RANK() OVER(ORDER BY Marks DESC) AS Rank FROM StudentMarks
Answer: B
Explanation:
Explanation/Reference:
Explanation: