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NEW QUESTION: 1
Which function allows you to check consistency of the dates within the project structure with or without taking activities into account?
Please choose the correct answer.
Response:
A. Sets of dates
B. Extrapolate
C. Check dates
D. Planning methods
Answer: C

NEW QUESTION: 2
A company named Fabricam, Inc, has a web app hosted in Microsoft Azure. Millions of users visit the app daily.
All of the user visits are logged in Azure Blob storage. Data analysts at Fabrikam built a dashboard that processes the user visit logs.
Fabrikam plans to use an Apache Hadoop cluster on Azure HDInsight to process queries. The queries will access the data only once.
You need to recommend a query execution strategy.
What is the best to recommend using to achieve the goal?
More than one answer choice may achieve the goal. Select the BEST answer.
A. Load the text files to ORC files, and then run dashboard queries on the ORC files.
B. Load the text files to sequence files, and then run dashboard queries on the sequence files.
C. Load the text files to parquet files, and then run dashboard queries on the parquet files.
D. Run the queries on the text files directly.
Answer: B
Explanation:
Explanation/Reference:
Explanation:
File format versatility and Intelligent caching: Fast analytics on Hadoop have always come with one big catch: they require up-front conversion to a columnar format like ORCFile, Parquet or Avro, which is time- consuming, complex and limits your agility.
With Interactive Query Dynamic Text Cache, which converts CSV or JSON data into optimized in-memory format on-the-fly, caching is dynamic, so the queries determine what data is cached. After text data is cached, analytics run just as fast as if you had converted it to specific file formats.
References: https://azure.microsoft.com/en-us/blog/azure-hdinsight-interactive-query-simplifying-big-data- analytics-architecture-and-operations/

NEW QUESTION: 3

A. Option C
B. Option A
C. Option D
D. Option B
Answer: B
Explanation:
Explanation
On R1, for IPV4 authentication of OSPF the command is missing and required to configure------ ip ospf authentication message-digest
Topic 4, Ticket 5 : NAT ACL
Topology Overview (Actual Troubleshooting lab design is for below network design)
* Client Should have IP 10.2.1.3
* EIGRP 100 is running between switch DSW1 & DSW2
* OSPF (Process ID 1) is running between R1, R2, R3, R4
* Network of OSPF is redistributed in EIGRP
* BGP 65001 is configured on R1 with Webserver cloud AS 65002
* HSRP is running between DSW1 & DSW2 Switches
The company has created the test bed shown in the layer 2 and layer 3 topology exhibits.
This network consists of four routers, two layer 3 switches and two layer 2 switches.
In the IPv4 layer 3 topology, R1, R2, R3, and R4 are running OSPF with an OSPF process number 1.
DSW1, DSW2 and R4 are running EIGRP with an AS of 10. Redistribution is enabled where necessary.
R1 is running a BGP AS with a number of 65001. This AS has an eBGP connection to AS 65002 in the ISP's network. Because the company's address space is in the private range.
R1 is also providing NAT translations between the inside (10.1.0.0/16 & 10.2.0.0/16) networks and outside (209.65.0.0/24) network.
ASW1 and ASW2 are layer 2 switches.
NTP is enabled on all devices with 209.65.200.226 serving as the master clock source.
The client workstations receive their IP address and default gateway via R4's DHCP server.
The default gateway address of 10.2.1.254 is the IP address of HSRP group 10 which is running on DSW1 and DSW2.
In the IPv6 layer 3 topology R1, R2, and R3 are running OSPFv3 with an OSPF process number 6.
DSW1, DSW2 and R4 are running RIPng process name RIP_ZONE.
The two IPv6 routing domains, OSPF 6 and RIPng are connected via GRE tunnel running over the underlying IPv4 OSPF domain. Redistrution is enabled where necessary.
Recently the implementation group has been using the test bed to do a 'proof-of-concept' on several implementations. This involved changing the configuration on one or more of the devices. You will be presented with a series of trouble tickets related to issues introduced during these configurations.
Note: Although trouble tickets have many similar fault indications, each ticket has its own issue and solution.
Each ticket has 3 sub questions that need to be answered & topology remains same.
Question-1 Fault is found on which device,
Question-2 Fault condition is related to,
Question-3 What exact problem is seen & what needs to be done for solution


Client is unable to ping IP 209.65.200.241
Solution
Steps need to follow as below:-
* When we check on client 1 & Client 2 desktop we are not receiving DHCP address from R4 Ipconfig ----- Client will be receiving IP address 10.2.1.3
* IP 10.2.1.3 will be able to ping from R4 , R3, R2, R1
* Look for BGP Neighbourship
Sh ip bgp summary ----- State of BGP will be in established state & will be able to receive I prefix (209.65.200.241)
* As per troubleshooting we are able to ping ip 10.2.1.3 from R1 & BGP is also receiving prefix of webserver & we are able to ping the same from R1. Further troubleshooting needs to be done on R1 on serial 0/0/1
* Check for running config. i.e sh run for interface serial 0/0/1..

!

!
From above snapshot we are able to see that IP needs to be PAT to serial 0/0/1 to reach web server IP (209.65.200.241). But in access-list of NAT IP allowed IP is 10.1.0.0/16 is allowed & need 10.2.0.0 /16 to
* As per troubleshooting we are able to ping ip 10.2.1.3 from R1 & BGP is also receiving prefix of web server & we are able to ping the same from R1. Its should be checked further for running config of interface for stopping
* Change required: On R1 we need to add the client IP address for reachability to server to the access list that is used to specify which hosts get NATed.

NEW QUESTION: 4
Refer to the exhibit.

What happens to a TCP packet that is received on interface GigabitEthernet 0/0/0.100, which has DF bit set to 1, and packet has a valid destination?
A. The packet is not matched by route-map foo and the DF bit is set to 0
B. The packet is not matched by route-map foo and the DF bit is left as it was
C. The packet is matched by route-map foo and the DF bit is left as it was
D. The packet is matched by route-map foo and the DF bit is set to 0
Answer: B