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NEW QUESTION: 1
When processing inbound Ethernet frames, which firewall filter is evaluated first by an EX Series switch?
A. VLAN filter
B. port filter
C. trunk filter
D. route filter
Answer: B
NEW QUESTION: 2
Which two components are critical for troubleshooting the Microsoft Dynamics GP Client? (Each correct answer presents a complete solution. Choose two.)
A. Session Host
B. Session Monitor
C. Tenant Discovery Service
D. Runtime Service
Answer: A,D
Explanation:
Understanding the components of the Web Client will be key in your planning and troubleshooting efforts. There are 9 specific components involved with getting the GP Web Client to function. Out of those 9 components, we would like to call out 4 components that we consider KEY and are troubleshooting components. This four components are:
Session Central Service Session Host Session Service Runtime Service
NEW QUESTION: 3
Die Unternehmenszentrale stellte Ihrem Büro einen Teil des Subnetzes der Klasse B zur Verfügung, das an einem neuen Bürostandort verwendet werden kann.
Gegebener Bereich: 172.30.232.0/24
* Verkauf von 57 Geräten
* HR 23 Geräte
* IT 12 Geräte
* 32 Geräte finanzieren
* Marketing 9 Geräte
ANLEITUNG
Weisen Sie die Mindestanzahl von Adressen (unter Verwendung der CIDR-Notation) zu, die für jede Abteilung erforderlich sind.
Identifizieren Sie nach der Unterbringung jeder Abteilung den nicht verwendeten Teil des Subnetzes, indem Sie auf die Frage in der Grafik antworten.
Alle Dropdowns müssen ausgefüllt sein.
Wenn Sie zu irgendeinem Zeitpunkt den Ausgangszustand der Simulation wiederherstellen möchten, klicken Sie auf die Schaltfläche Alle zurücksetzen.
Answer:
Explanation:
Explanation
Sales network - /26 - This will provide up to 62 usable IP addresses (64-2 for subnet and broadcast IP) HR network - /27 - This will provide for up to 30usable IP's (32-2) IT - /28 - This will provide for up to 14 usable IP's (16-2) Finance - /26 - Note that a /27 is 32 IP addresses but 2 of those are reserved for the network and broadcast IP's and can't be used for hosts.
Marketing - /28
If we add up how many IP blocks are used that is 64+32+16+64+16=192.
A /24 contains 256 IP addresses, so 256-192=64.
So the last unused box should be a /26, which equates to 64 addresses
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