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NEW QUESTION: 1
The following SAS program is submitted:
%let lib=%upcase(sauser); proc sql;
select nvar form dictionary.tables where libname='&lib"; quit;
Several SAS data sets exist in the SAUSER library.
What is generated as output?
A. A report showing the number of numeric columns in each table in SASUSER
B. A report showing the numeric columns in each table in SASUSER
C. A report showing the names of the columns in each table in SASUSER
D. A report showing the number of columns in each table in SASUSER
Answer: D

NEW QUESTION: 2
Sie erstellen eine Anwendung, die über eine SQL-Anmeldung mit dem Namen AgentPortalUser eine Verbindung zur AgentPortal-Datenbank herstellt. Gespeicherte Prozeduren in der Datenbank verwenden sp_send_dbmail, um E-Mail-Nachrichten zu senden.
Sie erstellen ein Benutzerkonto in der msdb-Datenbank für die AgentPortalUser-Anmeldung. Sie verwenden den Datenbank-Mail-Konfigurationsassistenten, um ein Datenbank-Mail-Profil zu erstellen. Für das Datenbank-E-Mail-Profil wurde keine Sicherheit konfiguriert.
Sie müssen sicherstellen, dass AgentPortalUser E-Mail-Nachrichten senden kann.
Was tun?
A. Erstellen Sie im Datenbank-E-Mail-Konfigurations-Assistenten ein E-Mail-Konto für die E-Mail-Adresse jedes Empfängers im Datenbank-E-Mail-Profil.
B. Aktivieren Sie den Gastbenutzer in der msdb-Datenbank.
C. Konfigurieren Sie im Datenbank-Mail-Konfigurationsassistenten das Datenbank-Mail-Profil als privates Profil für AgentPortalUser
D. Konfigurieren Sie den AgentPortalUser-Benutzer als Mitglied von SQLAgentOperationRole in der msdb-Datenbank.
Answer: C
Explanation:
Erläuterung
Zum Senden von Datenbank-E-Mails müssen Sie Mitglied der DatabaseMailUserRole-Datenbankrolle in der msdb-Datenbank sein.

NEW QUESTION: 3
Refer to the Exhibit.

A storage administrator has reported that full utilization of all bandwidth from an ESXi 6.x host is not being seen. In troubleshooting the issue, the Adapter details are shown in the Exhibit.
Based on the exhibit, what is cause of the issue?
A. The array is not setup to use the correct multipathing policy.
B. There are no virtual machines on the ESXi host.
C. Another path needs to be configured.
D. Not all links are used because a path is disabled.
Answer: D
Explanation:
Explanation/Reference:
Explanation:
The cause might be that not all links are used because a path is disabled as you can see in the third row.
Reference:

NEW QUESTION: 4
Which two statements are true regarding the USING clause in table joins?(Choose two.)
A. It can be used to join a maximum of three tables.
B. It can be used to access data from tables through equijoins as well as nonequijoins.
C. It can be used to join tables that have columns with the same name and compatible data types.
D. It can be used to restrict the number of columns used in a NATURAL join.
Answer: C,D
Explanation:
Explanation/Reference:
Explanation:
NATURAL JOIN operation
A NATURAL JOIN is a JOIN operation that creates an implicit join clause for you based on the common columns in the two tables being joined. Common columns are columns that have the same name in both tables.
If the SELECT statement in which the NATURAL JOIN operation appears has an asterisk (*) in the select list, the asterisk will be expanded to the following list of columns (in this order):
All the common columns
Every column in the first (left) table that is not a common column
Every column in the second (right) table that is not a common column
An asterisk qualified by a table name (for example, COUNTRIES.*) will be expanded to every column of that table that is not a common column.
If a common column is referenced without being qualified by a table name, the column reference points to the column in the first (left) table if the join is an INNER JOIN or a LEFT OUTER JOIN. If it is a RIGHT OUTER JOIN, unqualified references to a common column point to the column in the second (right) table.
Syntax
TableExpression NATURAL [ { LEFT | RIGHT } [ OUTER ] | INNER ] JOIN
{ TableViewOrFunctionExpression |
( TableExpression ) }
Examples
If the tables COUNTRIES and CITIES have two common columns named COUNTRY and COUNTRY_ISO_CODE, the following two SELECT statements are equivalent:
SELECT * FROM COUNTRIES NATURAL JOIN CITIES
SELECT * FROM COUNTRIES JOIN CITIES
USING (COUNTRY, COUNTRY_ISO_CODE)