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NEW QUESTION: 1


Answer:
Explanation:

Explanation

Step 1: Stop VM1.
Step 2: Detach Disk1 from VM1.
Step 3: Start VM1.
Detach a data disk using the portal
* In the left menu, select Virtual Machines.
* Select the virtual machine that has the data disk you want to detach and click Stop to deallocate the VM.
* In the virtual machine pane, select Disks.
* At the top of the Disks pane, select Edit.
* In the Disks pane, to the far right of the data disk that you would like to detach, click the Detach button image detach button.
* After the disk has been removed, click Save on the top of the pane.
* In the virtual machine pane, click Overview and then click the Start button at the top of the pane to restart the VM.
* The disk stays in storage but is no longer attached to a virtual machine.
Step 4: Attach Disk1 to VM2
Attach an existing disk
Follow these steps to reattach an existing available data disk to a running VM.
* Select a running VM for which you want to reattach a data disk.
* From the menu on the left, select Disks.
* Select Attach existing to attach an available data disk to the VM.
* From the Attach existing disk pane, select OK.
References:
https://docs.microsoft.com/en-us/azure/virtual-machines/windows/detach-disk
https://docs.microsoft.com/en-us/azure/lab-services/devtest-lab-attach-detach-data-disk

NEW QUESTION: 2
What happens when you attempt to compile and run the following code?
# include <vector>
# include <iostream>
# include <algorithm>
using namespace std;
template<class T>struct Out {
ostream & out;
Out(ostream & o): out(o){}
void operator() (const T & val ) { out<<val<<" "; } };
struct Add {
int operator()(int & a, int & b) {
return a+b;
}
};
int main() {
int t[]={1,2,3,4,5,6,7,8,9,10};
vector<int> v1(t, t+10);
vector<int> v2(10);
transform(v1.begin(), v1.end(), v2.begin(), bind1st(1,Add()));
for_each(v2.rbegin(), v2.rend(), Out<int>(cout));cout<<endl;
return 0;
}
Program outputs:
A. compilation error
B. 11 10 9 8 7 6 5 4 3 2
C. 2 3 4 5 6 7 8 9 10 11
D. 10 9 8 7 6 5 4 3 2 1
E. 1 2 3 4 5 6 7 8 9 10
Answer: A

NEW QUESTION: 3


Answer:
Explanation:

Explanation

* accepts : 'application/bint, text/xml'
accepts:'application/bin,text/xml' to accept only XML and binary content in HTML responses.
* Use the following condition to check if the html response content is
binary: If(request.getResponseHeader("Content-Type")=="application/bint"
* var request = $.ajax({
uri:'/',
accepts: 'application/bint, text/xml',
datafilter: function(data,type){
if(request.getResponseHeader("Content-Type")=="application/bint")
return parseBint(data);
else
return parseXml();
},
success: function (data) {
start(data);
}
});

NEW QUESTION: 4

A. Option B
B. Option C
C. Option A
D. Option D
Answer: B,C