Integrated-Physical-Sciences Practice Questions

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NEW QUESTION: 1
Your network contains a System Center 2012 Configuration Manager environment.
You need to create a report that lists all of the client computers that do not have an Application named App1 instated.
Which query should you use to create the report?
A. SELECT SYS.Netbios_Name0, ARP.DisplayName0 FROM v_R_System AS SYS INNER JOIN v_GS_ADD_REMOVE_PROGRAMS AS ARP ON SYS.ResourceID = ARP. ResourceID WHERE ARP.DisplayName0 NOT IN ('App1')
B. SELECT SYS.Netbios_Name0, ARP.DisplayName0 FROM v_R_System AS SYS INNER JOIN V_GS_ADD_REMOVE_PROGRAMS AS ARP ON SYS.ResourceID - ARP.ResourceID WHERE ARP.DisplayName0 NOT LIKE 'App1'
C. SELECT SYS.Netbios_Name0 from v_R_System SYS WHERE SYS.ResourceID NOT IN (SELECT SYS.ResourceID FROM v_R_System AS SYS INNER JOIN v_GS_ADD_REMOVE_PROGRAMS AS ARP ON SYS.ResourceID = ARP.ResourceID WHERE ARP. DisplayName0 = 'App1')
D. SELECT SYS.Netbios_Name0 from v_R_System SYS WHERE SYS.ResourceID IN (SELECT SYS.ResourceID FROM v_R_System AS SYS INNER JOIN v_GS_ADD_REMOVE_PROGRAMS AS ARP ON SYS.ResourceID - ARP.ResourceID. WHERE ARP. DisplayName0 = 'App1')
Answer: C
Explanation:
The inner expression listed below would result in an empty result if the client computer does not have an application named App1.
Inner expression: (SELECT SYS.ResourceID FROM v_R_System AS SYS INNER JOIN v_GS_ADD_REMOVE_PROGRAMS AS ARP ON SYS.ResourceID = ARP.ResourceID WHERE ARP. DisplayName0 = 'App1')

NEW QUESTION: 2
コードの断片を考えると：

結果は何ですか？
A. A B C D Work done
B. A Work done
C. A B C Work done
D. Compilation fails.
Answer: B

NEW QUESTION: 3

A. Option A
B. Option B
C. Option D
D. Option C
Answer: A,B,C

NEW QUESTION: 4
Ziehen Sie die IPv4-Netzwerksubnetze von links auf die richtigen verwendbaren Hostbereiche rechts

Answer:
Explanation: