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NEW QUESTION: 1
What is Sharing Rule?
A. Exceptions to Org. wide Defaults
B. Irrelevant for Public Read / Write Organizations
C. Rules given for group of user working closely on a project
D. Automated rules that grant access to groups of users
Answer: A,B,D

NEW QUESTION: 2
Which of these is the equation used to derive a 64 Kbps bit rate?
A. 2 x 8 kHz x 4-bit code words
B. 2 x 4 kHz x 8-bit code words
C. 8 kHz x 8-bit code words
D. 2 x 4-bit code words x 8 kHz
Answer: B
Explanation:
While the human ear can sense sounds from 20 to 20, 000 Hz, and speech encompasses sounds
from about 200 to 9000 Hz, the telephone channel was designed to operate at about 300 to 3400
Hz. This economical range carries enough fidelity to allow callers to identify the party at the far end
and sense their mood. Nyquist decided to extend the digitization to 4000 Hz, to capture higher-
frequency sounds that the telephone channel may deliver. Therefore, the highest frequency for
voice is 4000 Hz. According to Nyquist theory, we must double the highest frequency, so 2x4kHz
= 8kHz.
Each sample will be encoded into a 8-bit code. Therefore 8kHz x 8-bit code = 64 Kbps (notice
about the unit Kbps: 8kHz = 8000 samples per second so 8000 x 8-bit = 64000 bit per second =
64 Kilobit per second = 64 Kbps)
Link: http://encyclopedia2.thefreedictionary.com/Nyquist+theorem
Note:
Nyquist theory:
"When sampling a signal (e.g., converting from an analog signal to digital), the sampling frequency
must be greater than twice the bandwidth of the input signal in order to be able to reconstruct the
original perfectly from the sampled version."

NEW QUESTION: 3
IS-IS routers with an interface priority of 0 can't participate in DIS election.
A. False
B. True
Answer: A

NEW QUESTION: 4
An engineer is using Cisco Jabber. Instant messages are transported through which protocol?
A. XMPP
B. SCCP
C. H.323
D. SIP
Answer: A