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NEW QUESTION: 1
Where is the tenancy Oracle Cloud Identifier (OCID) located?
A. given by support on account creation
B. on the Identity - Users page
C. at the bottom of every console page
D. contained within the compartment OCID
Answer: C
Explanation:
Explanation/Reference:
Reference: https://docs.cloud.oracle.com/iaas/Content/General/Concepts/identifiers.htm#two

NEW QUESTION: 2
Examine the following command that is used to duplicate a database on the same host:
RMAN> RUN { ALLOCATE AUXILIARY CHANNEL aux 1 DEVICE TYPE DISK; DUPLICATE TARGET DATABASE TO auxdb SKIP READONLY; }
Which two statements describe the effect after the database is duplicated successfully? (Choose two)
A. The data files of the read-only tablespaces in the target database get duplicated
B. The read-only tablespaces in the target database are changed to online after duplication
C. The read-only tablespaces in the target database are still defined in new the database
D. The read-only tablespaces in the target database are not defined in the new database
E. The data files of the read-only tablespaces in the target database are not duplicated
Answer: C,E

NEW QUESTION: 3
Note: This question is part of a series of questions that use the same or similar answer choices. An answer choice may be correct for more than one question in the series. Each question is independent of the other questions in this series. Information and details provided in a question apply to that question.
You have a database for a banking system. The database has two tables named tblDepositAcct and tblLoanAcct that store deposit and loan accounts, respectively/ Both tables contain the following columns:

You need to run a query to find the total number of customers who have both deposit and loan accounts.
Which Transact-SQL statement should you run?
A. SELECT COUNT(DISTINCT L.CustNo)FROM tblDepositAcct DRIGHT JOIN
tblLoanAcct L ON D.CustNo = L.CustNoWHERE D.CustNo IS NULL
B. CustNo
C. CustNo IS NULL
D. SELECT COUNT(*)FROM tblDepositAcct DFULL JOIN tblLoanAcct L ON D.CustNo
E. SELECT COUNT (DISTINCT D.CustNo)FROM tblDepositAcct D, tblLoanAcct LWHERE
F. SELECT COUNT(*)FROM (SELECT AcctNoFROM tblDepositAcctINTERSECTSELECT AcctNoFROM tblLoanAcct) R
G. CustNo = L.CustNo
H. SELECT COUNT(*)FROM (SELECT CustNoFROM tblDepositAcctUNION ALLSELECT CustNoFROM tblLoanAcct) R
I. SELECT COUNT(*)FROM (SELECT CustNoFROM tblDepositAcctUNIONSELECT
CustNoFROM tblLoanAcct) R
J. SELECT COUNT (DISTINCT COALESCE(D.CustNo, L.CustNo))FROM tblDepositAcct DFULL JOIN tblLoanAcct L ON D.CustNo = L.CustNoWHERE D.CustNo IS NULL OR
K. SELECT COUNT(*)FROM (SELECT CustNoFROM tblDepositAcctEXCEPTSELECT
CustNoFROM tblLoanAcct) R
Answer: F
Explanation:
The SQL INTERSECT operator is used to return the results of 2 or more SELECT statements. However, it only returns the rows selected by all queries or data sets. If a record exists in one query and not in the other, it will be omitted from the INTERSECT results.
References: https://www.techonthenet.com/sql/intersect.php

NEW QUESTION: 4
Which action can you perform with a Lookup view?
A. Set the Lookup view as the default view.
B. Create a new view based on the Lookup view.
C. Delete the Lookup view.
D. Customize the Lookup view.
Answer: D