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NEW QUESTION: 1
You configure Just Enough Administration (JEA).
You need to ensure that a non-administrator user can perform the following actions:
-Restart Internet Information Services (IIS)
-Restart a custom service named Service1.
How should you complete the role configuration file? To answer, select the appropriate options in the answer area.

Answer:
Explanation:

Explanation

VisibleExternalCommands = 'C:\\Windows\\system32\\iisreset.exe'
VisibleCmdlets = @{ Name 'Restart-service' ; Parameters @{ Name = 'Name'; ValidateSet = 'Service1'}}
https://docs.microsoft.com/en-us/powershell/jea/role-capabilities

NEW QUESTION: 2
If you plan to use the Cisco Unified Communications Manager Bulk Administration Tool, which feature service must you activate on the first node to administer phones and users?
A. Cisco Dynamic Host Configuration Protocol Monitor service
B. Cisco WebDialer Web service
C. Cisco Bulk Provisioning service
D. Cisco AXL Web service
Answer: C

NEW QUESTION: 3
企業には、5つの独立したAWS Lambda関数で構成されるアプリケーションがあります。 DevOpsエンジニアは、AWS CodePipelineとAWS CodeBuildを使用してCI / CDパイプラインを構築し、各Lambda関数を順にビルド、テスト、パッケージ化、デプロイしました。パイプラインはAmazon CloudWatchイベントルールを使用して、アプリケーションのソースコードに変更が加えられた後、パイプラインの実行が可能な限り迅速に開始されるようにします。
数か月間パイプラインを操作した後、DevOpsエンジニアは、パイプラインの完了に時間がかかりすぎることに気付きました。
パイプラインの速度を最高に改善するには、DevOpsエンジニアが何を実装する必要がありますか？
A. ビルドを並列で実行する対称型マルチプロセッシング構成を含むカスタムCodeBuild実行環境を作成します。
B. パイプライン内のCodeBuildプロジェクトを変更して、利用可能なネットワークスループットがより高いコンピューティングタイプを使用します。
C. 同じrunOrderを指定して、各Lambda関数のアクションを並列で実行するようにCodePipeline構成を変更します。
D. VPC内で実行されるように各CodeBuildプロジェクトを変更し、専用インスタンスを使用してスループットを向上させます。
Answer: C
Explanation:
Explanation
https://aws.amazon.com/blogs/devops/using-aws-codepipeline-aws-codebuild-and-aws-lambda-for-serverless-au
https://docs.aws.amazon.com/codepipeline/latest/userguide/reference-pipeline-structure.html

NEW QUESTION: 4
You need to retrieve the username cookie from an HTTP request. If this cookie does NOT exist, then the c variable will be null. Which code snippet must be used to retrieve this cookie object?
A. 10. Cookie c = null;
1 1. for ( Enumeration e = request.getCookies();
1 2. e.hasMoreElements(); ) {
1 3. Cookie o = (Cookie) e.nextElement();
1 4. if ( o.getName().equals("username") ) {
1 5. c = o;
1 6. break;
1 7. }
1 8. }
B. 10. Cookie c = null;
1 1. Cookie[] cookies = request.getCookies();
1 2. for ( int i = 0; i < cookies.length; i++ ) {
1 3. if ( cookies[i].getName().equals("username") ) {
1 4. c = cookies[i];
1 5. break;
1 6. }
1 7. }
C. 10. Cookie c = request.getCookie("username");
D. 10. Cookie c = null;
1 1. for ( Iterator i = request.getCookies();
1 2. i.hasNext(); ) {
1 3. Cookie o = (Cookie) i.next();
1 4. if ( o.getName().equals("username") ) {
1 5. c = o;
1 6. break;
1 7. }
1 8. }
Answer: B