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NEW QUESTION: 1
プロジェクトマネージャーは、新しいシステムを展開するプロジェクトを主導するように割り当てられています。利害関係者はプロジェクトの目的とアプローチに同意しませんプロジェクトマネージャーは何をすべきですか？
A. プロジェクトチームとスコーピングワークショップを実施して、作業分解図（WBS）を作成し、さまざまなエンティティにタスクを割り当てて、これをすべての利害関係者と共有し、チームにスケジュールどおりにタスクを完了するように依頼します。
B. プロジェクト憲章に基づいて役割と責任のマトリックスを作成し、信頼できる権限を提供するためにすべての利害関係者と共有するようスポンサーに依頼します
C. すべての利害関係者との総会を実施し、各利害関係者の活動のリストを確認して対処します
D. 状況を分析して不一致の根本原因を特定し、各利害関係者および参加エンティティと正確な役割と責任について協力します
Answer: D

NEW QUESTION: 2
Your network consists of a single Active Directory domain. The domain contains a server that runs Windows Server 2008 R2. The server has Microsoft SharePoint Foundation 2010 installed. You need to allow users to create distribution lists from a SharePoint site. What should you do on the SharePoint Foundation 2010 server?
A. Set the outgoing mail character set to 1200(Unicode).
B. Configure the site to use the default Rights Management server in Active Directory Domain Services.
C. Enable the SharePoint Directory Management Service.
D. Configure the site to accept messages from authenticated users only.
Answer: C
Explanation:
To configure WSS server in such a way that it allow users to create distribution lists from a SharePoint site, you need to enable the SharePoint Directory Management Service on the server. A distribution list contains the email addresses of existing address lists as well as the email addresses of other site members. Distribution lists are available only if the SharePoint Directory Management Service is enabled in Central Administration.
All new subsites that are created in an email-enabled site collection are automatically email-enabled also. If you choose to use an existing group during site creation, the distribution list for the parent site (if available) will be associated with the new site
Reference: Introduction to incoming email/ New site creation walkthrough
http://office.microsoft.com/en-us/help/HA100823061033.aspx

NEW QUESTION: 3
Given the network diagram.

Which address would successfully summarize only the networks seen?
A. These networks cannot be summarized.
B. 192.168.12.0/20
C. 192.168.8.0/20
D. 192.168.8.0/21
E. 192.168.16.0/21
F. 192.168.0.0/24
Answer: D
Explanation:
let's suppose it is a /20 then we would have addresses from 192.168.0.1 to 192.168.15.255 Now let's suppose it is a /21 then we would have addresses from 192.168.8.1 to
192.168.15.255
So both summaries encompass the networks we want to summarize but the second one is the most restrictive one as it only encompasses the networks we were asked to summarize and not others so it is the correct summary.
In fact just count the number of subnets which is 8 and find the exponent of 2 which is 8, that gives you 3 and to find out the summary mask just do /24 - 3 = /21.
if you make it in binary you'll find out the answer too:
the interesting octet is 3rd one so let's convert in binary.
8 0000 1000
9 0000 1001
1 0 0000 1010
1 1 0000 1011
1 2 0000 1100
1 3 0000 1101
1 4 0000 1110
1 5 0000 1111
I've bolded the bits in common there are 5 so 16+5=21 which is mask and address is
1 92.168.8.0

NEW QUESTION: 4
Where would you look to find the minimum and the maximum number of array LUNs supported by FlexArray?
A. Config Advisor
B. Hardware Universe
C. OneCollect
D. Interoperability Matrix Tool (IMT)
Answer: B