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NEW QUESTION: 1
Java例外メカニズムの利点はどれですか？ （3つ選択してください。）
A. プログラマーが例外を処理する場所を選択できるため、プログラム構造が改善されます。
B. エラー処理コードが通常のプログラム機能から分離されているため、プログラム構造が改善されます。
C. 考えられるすべてのエラーをカバーする一連の標準例外を提供します
D. 例外は発生したメソッドで処理する必要があるため、プログラム構造を改善します。
E. 作成中の特定のプログラムにカスタマイズされた新しい例外の作成を許可します
Answer: A,B,E

NEW QUESTION: 2
Which changes, introduced independently, will allow the code to compile and display "one" "eight" "nine"
"ten"? Choose all that apply
#include <iostream>
#include <map>
#include <string>
using namespace std;
class A {
int a;
public:
A(int a):a(a){}
int getA() const { return a;}
/* Insert Code Here 1 */
};
/* Insert Code Here 2 */
int main(){
int t[] ={ 3, 4, 2, 1, 6, 5, 7, 9, 8, 10 };
string s[] = {"three", "four", "two", "one", "six","five", "seven", "nine","eight","ten"}; map<A, string> m;/* Replace Code Here 3 */ for(int i=0; i<10; i++) { m.insert(pair<A,string>(A(t[i]),s[i]));
}
m.erase(m.lower_bound(2),m.upper_bound(7));
map<A, string>::iterator i=m.begin(); /* Replace Code Here 4 */
for( ;i!= m.end(); i++) {
cout<<i?>second<<" ";
}
cout<<endl;
return 0;
}
A. operator int() const { return a;} inserted at Place 1
B. struct R { bool operator ()(const A & a, const A & b) { return a.getA()<b.getA();} }; inserted at Place 2 replacing line marked 3 with map<A, string, R> m; replacing line marked 4 with map<A, string,R>::iterator i=m.begin();
C. bool operator < (const A & b) const { return a<b.a;} inserted at Place 1
D. bool operator < (const A & b) const { return b.a<a;} inserted at Place 1
Answer: A,B,C

NEW QUESTION: 3
회사는 최근 웹, 애플리케이션 및 NoSQL 데이터베이스 계층을 AWS로 마이그레이션했습니다. 이 회사는 Auto Scaling을 사용하여 웹 및 애플리케이션 계층을 확장하고 있습니다. Amazon DynamoDB 요청의 95 % 이상이 읽기 요청을 반복합니다.
반복되는 요청을 캐시하도록 DynamoDB NoSQL 계층을 어떻게 확장 할 수 있습니까?
A. Amazon DynamoDB 액셀러레이터
B. Amazon SQS
C. Amazon CloudFront
D. Amazon EMR
Answer: A
Explanation:
Reference:
https://aws.amazon.com/dynamodb/dax/

NEW QUESTION: 4
ABC, Inc. is a medium sized company, with an enterprise network (access, distribution and core switches) that provides LAN connectivity from user PCs to corporate servers. The distribution switches are configured to use HSRP to provide a high availability solution.
DSW1 - primary device for VLAN 101 VLAN 102 and VLAN 105

DSW2 - primary device for VLAN 103 and VLAN 104

A failure of GigabitEthemet1/0/1 on primary device should cause the primary device to release its

status as the primary device, unless GigabitEthernet1/0/1 on backup device has also failed.
Troubleshooting has identified several issues. Currently all interfaces are up. Using the running configurations and show commands, you have been asked to investigate and respond to the following question.



During routine maintenance, it became necessary to shut down the GigabitEthernet1/0/1 interface on DSW1. All other interfaces were up. During this time, DSW1 remained the active device for the VLAN 102 HSRP group. You have determined that there is an issue with the decrement value in the track command for the VLAN 102 HSRP group. What needs to be done to make the group function properly?
A. The decrement value on DSW1 should be greaterthan 11 and less than 19.
B. The decrement value on DSWTs should be greaterthan 195 and less than 205.
C. The decrement value on DSW1 should be greaterthan 5 and less than 15. 0
D. The decrement value on DSW1 should be greaterthan 9 and less than 15.
E. The decrement value on DSWTs should be greaterthan 190 and less than 200.
Answer: A
Explanation:
Explanation/Reference:
Explanation:

Use "show run" command to show. The left Vlan102 is console1 of DS1. Priority value is 200, we should decrement value in the track command from 11 to 18. Because 200 - 11 = 189 < 190 (priority of Vlan102 on DS2).