CRT-251 Practice Questions

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NEW QUESTION: 1
First National Bancshares, Inc., a bank holding company, filed an application with its Federal Reserve Bank on March 1 to acquire a subsidiary bank. On March 15 the Federal Reserve Board asked First National for more information. On April 1 the Federal Reserve Bank received the completed application and accepted it. On April 5 the Federal Reserve Bank notified First National of the April 1 acceptance and referred the application to the Federal Reserve Board. Under the normal rules, by what date must the Federal Reserve Board act on the application?
A. July 1
B. April 30
C. June 1
D. June 5
Answer: C

NEW QUESTION: 2
테스트 할 샘플을 선택하십시오. 여기에는 80 개의 가장 큰 고객 잔액과 나머지 샘플이 무작위로 포함되어야 합니다. IS 감사인은 다음을 권장해야 합니다.
A. 통합 테스트 시설 (ITF) 개발.
B. 유틸리티 릴리스 관리를 사용하여 파일 정렬
C. 일반화된 감사 소프트웨어 사용.
D. 소프트웨어를 사용하여 속성 샘플링을 적용합니다.
Answer: C

NEW QUESTION: 3
가동 중지 시간이 가장 낮은 재해 복구 시나리오는 무엇입니까?
A. 백업 및 복원
B. 다중 사이트 활성-활성
C. 파일럿 라이트
D. 웜 대기
Answer: B
Explanation:
Backup and Restore: a simple, straightforward, cost-effective method that backs up and restores data as needed. Keep in mind that because none of your data is on standby, this method, while cheap, can be quite time-consuming.
Pilot Light: This method keeps critical applications and data at the ready so that it can be quickly retrieved if needed.
Warm Standby: This method keeps a duplicate version of your business' core elements running on standby at all times, which makes for a little downtime and an almost seamless transition.
Multi-Site Solution: Also known as a Hot Standby, this method fully replicates your company's data/applications between two or more active locations and splits your traffic/usage between them. If a disaster strikes, everything is simply rerouted to the unaffected area, which means you'll suffer almost zero downtime. However, by running two separate environments simultaneously, you will obviously incur much higher costs.

NEW QUESTION: 4
View the exhibit and examine the structure of ORDERSand CUSTOMERStables.

Which INSERT statement should be used to add a row into the ORDERStable for the customer whose CUST_LAST_NAMEis Robertsand CREDIT_LIMITis 600? Assume there exists only one row with CUST_LAST_NAME as Roberts and CREDIT_LIMIT as 600.
A. INSERT INTO orders (order_id, order_date, order_mode,
( SELECT customer id
FROM customers
WHERE cust_last_name='Roberts' AND credit_limit=600), order_total);
VALUES (1,'10-mar-2007', 'direct', &customer_id, 1000);
B. INSERT INTO orders
VALUES (1,'10-mar-2007', 'direct',
( SELECT customer_id
FROM customers
WHERE cust_last_name='Roberts' AND credit_limit=600), 1000);
C. INSERT INTO (SELECT o.order_id, o.order_date, o.order_mode, c.customer_id, o.order_total FROM orders o, customers c
WHERE o.customer_id = c.customer_id AND c.cust_last_name='Roberts' AND
c.credit_limit=600)
VALUES (1,'10-mar-2007', 'direct', (SELECT customer_id
FROM customers
WHERE cust_last_name='Roberts' AND credit_limit=600), 1000);
D. INSERT INTO orders (order_id, order_date, order_mode,
( SELECT customer_id
FROM customers
WHERE cust_last_name='Roberts' AND credit_limit=600), order_total);
VALUES (1,'10-mar-2007', 'direct', &customer_id, 1000);
Answer: B