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NEW QUESTION: 1
Your network contains an Active Directory domain named contoso.com. The domain contains domain controllers that run Windows Server 2008, Windows Server 2008 R2 Windows Server 2012, and Windows Server 2012 R2.
A domain controller named DC1 runs Windows Server 2012 R2. DC1 is backed up daily.
During routine maintenance, you delete a group named Group1.
You need to recover Group1 and identify the names of the users who were members of Group1 prior to its deletion. You want to achieve this goal by using the minimum amount of administrative effort.
What should you do first?
A. Perform an authoritative restore of Group1.
B. Mount the most recent Active Directory backup.
C. Use the Recycle Bin to restore Group1.
D. Reactivate the tombstone of Group1.
Answer: A
Explanation:
The Active Directory Recycle Bin does not have the ability to track simple changes to objects. If the object itself is not deleted, no element is moved to the Recycle Bin for possible recovery in the future. In other words, there is no rollback capacity for changes to object properties, or, in other words, to the values of these properties.
There is another approach you should be aware of. Tombstone reanimation (which has nothing to do with zombies) provides the only way to recover deleted objects without taking a DC offline, and it's the only way to recover a deleted object's identity information, such as its objectGUID and objectSid attributes. It neatly solves the problem of recreating a deleted user or group and having to fix up all the old access control list (ACL) references, which contain the objectSid of the deleted object.
Restores domain controllers to a specific point in time, and marks objects in Active Directory as being authoritative with respect to their replication partners.

NEW QUESTION: 2
The boundary separating the TCB from the remainder of the system is
called the:
A. Star property.
B. Discretionary control boundary.
C. Security perimeter.
D. Simple security property.
Answer: C
Explanation:
The correct answer is Security perimeter. Answers Star property and Simple security property deal with security models and answer Discretionary control boundary is a distracter.

NEW QUESTION: 3
An administrator has installed the latest HFA on the system for fixing traffic problems after creating a backup file. A large number of routes were added or modified, causing network problems. The Check Point configuration has not been changed. What would be the most efficient way to revert to a working configuration?
A. Use the command restore and select the appropriate backup file.
B. A back up cannot be restored, because the binary files are missing.
C. Select Snapshot Management from the SecurePlatform boot menu.
D. The restore is not possible because the backup file does not have the same build number (version).
Answer: A

NEW QUESTION: 4
Refer to the exhibit. The network is converged.After link-state advertisements are received from Router_A, what information will Router_E contain in its routing table for the subnets 208.149.23.64 and
208.149.23.96?

A. 208.149.23.64[110/13] via 190.173.23.10, 00:00:07, Serial1/0 208.149.23.96[110/13] via
190.173.23.10,
00:00:16, Serial1/0 208.149.23.96[110/13] via 190.173.23.10, 00:00:16, FastEthemet0/0
B. 208.149.23.64[110/1] via 190.172.23.10, 00:00:07, Serial1/0 208.149.23.96[110/3] via 190.173.23.10,
00:00:16, FastEthemet0/0
C. 208.149.23.64[110/13] via 190.173.23.10, 00:00:07, FastEthemet0/0 208.149.23.96[110/13] via
190.173.23.10, 00:00:16, FastEthemet0/0
D. 208.149.23.64[110/3] via 190.172.23.10, 00:00:07, Serial1/0 208.149.23.96[110/3] via 190.173.23.10,
00:00:16, Serial1/0
Answer: C
Explanation:
Explanation/Reference:
Explanation:
Router_E learns two subnets subnets 208.149.23.64 and 208.149.23.96 via Router_A through FastEthernet interface. The interface cost is calculated with the formula 108 / Bandwidth. For FastEthernet it is 108 / 100 Mbps = 108 / 100,000,000 = 1. Therefore, the cost is 12 (learned from Router_A) + 1 = 13 for both subnets -> The cost through T1 link is much higher than through T3 link (T1 cost = 108 / 1.544 Mbps = 64; T3 cost
108 / 45 Mbps = 2) so surely OSPF will choose the path through T3 link -> Router_E will choose the path from Router_A through FastEthernet0/0, not Serial1/0. In fact, we can quickly eliminate answers B, C and D because they contain at least one subnet learned from Serial1/0 -> they are surely incorrect.