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NEW QUESTION: 1
Your customer has the following requirement: when filtering service requests an agent wants to see by default all those service requests that are "New", whose channel type is "Web", and are assigned to them. Which five activities should be completed by an agent on the SR list page in order to create an appropriate personalized service request search filter?
A. In Advanced Search, select Action > Update.
B. In Advanced Search, save and select the "Set as Default" box.
C. Change the section identified with Status = New.
D. In Advanced Search, Add Channel Type * Web.
E. In Advanced Search, confirm Record Set = Assigned to Me.
F. Click the Show Advanced Search icon.
Answer: B,C,D,E,F

NEW QUESTION: 2
카탈로그 서버. 도메인 구조에는 하나의 루트 도메인과 하나의 자식 도메인이 있습니다. 자식 도메인에 있는 파일 서버에서 폴더 권한을 수정합니다. 일부 액세스 제어 항목은 S-1-5-21로 시작하며 계정 이름이 표시되지 않습니다.
계정 이름을 나열해야 합니다. 어떻게 해야 합니까?
A. 자식 도메인의 RID 마스터 역할을 글로벌 카탈로그를 보유한 도메인 컨트롤러로 이동하십시오.
B. 친숙한 이름 속성을 글로벌 카탈로그에 복제 할 수 있도록 스키마를 수정하십시오.
C. 자식 도메인의 인프라 마스터 역할을 글로벌 카탈로그를 보유하지 않은 도메인 컨트롤러로 옮깁니다.
D. 자식 도메인의 RID 마스터 역할을 글로벌 카탈로그를 보유하지 않은 도메인 컨트롤러로 이동하십시오.
Answer: C
Explanation:
설명
IM FSMO (Flexible Single Master Operation) 역할 소유자도 글로벌 카탈로그 서버 인 경우 해당 도메인 컨트롤러에서 팬텀 인덱스가 만들어 지거나 업데이트되지 않습니다. FSMO는 작업 마스터라고도 합니다.이 문제는 글로벌 카탈로그 서버에 Active Directory의 모든 개체에 대한 부분 복제본이 포함되어 있기 때문에 발생합니다. IM은 이미 로컬 글로벌 카탈로그에 개체의 부분 복제본이 있으므로 가상 버전의 외부 개체를 저장하지 않습니다.
이 프로세스가 다중 도메인 환경에서 올바르게 작동하려면 인프라 FSMO 역할 소유자가 글로벌 카탈로그 서버가 될 수 없습니다. 포리스트의 첫 번째 도메인은 5 개의 FSMO 역할을 모두 보유하며 글로벌 카탈로그이기도 합니다. 따라서 여러 도메인을 사용하려는 경우 도메인에 다른 도메인 컨트롤러가 설치 되 자마자 두 역할을 다른 컴퓨터로 이전해야 합니다.

NEW QUESTION: 3
Given the code fragments:

Which action completes this composite primary key implementation?
A. Add @IdClass(ContactId.class) annotation at line 2.
B. Add @Embeddable annotation at line 1 and replace both @Id annotations with @EmbeddedId annotations.
C. Add @Embeddable annotation at line 1 and @EmbeddedId(ContactId.class) at line 2.
D. Add @IdClass annotation at line 1.
Answer: C

NEW QUESTION: 4
CORRECT TEXT
What is the most appropriate declaration for the variable A?
A = 'ABCDEF';
A. DCL A CHAR(6);
B. DCL A PlC '999999';
C. DCL A BIN FIXED(15);
D. DCL A DEC FIXED (153);
Answer: A