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NEW QUESTION: 1
You are creating a new case.
You need to associate the case to a specific customer.
What are two possible types of records that you can use to achieve the goal? Each correct answer presents a complete solution
A. account
B. custom entity
C. lead
D. contact
Answer: B,C

NEW QUESTION: 2





A. SELECT Name, Country, Orderld, OrderDate, AmountFROM OrdersINNER JOIN CustomersON Orders.CustomerId = Customers.CustomerIdWHERE Customers.CustomerId = 1FOR XML AUTO, ELEMENTS
B. SELECT OrderId, OrderDate, Amount, Name, CountryFROM OrdersINNER JOIN CustomersON Orders.CustomerId = Customers.CustomerIdWHERE Customers.CustomerId = 1FOR XML AUTO, ELEMENTS
C. SELECT OrderId, OrderDate, Amount, Name, CountryFROM OrdersINNER JOIN Customers ON Orders.CustomerId = Customers-CustomerIdWHERE Customers.CustomerId = 1FOR XML RAW
D. SELECT OrderId, OrderDate, Amount, Name, CountryFROM OrdersINNER JOIN CustomersON Orders.CustomerId = Customers.CustomerIdWHERE Customers.CustomerId = 1FOR XML AUTO
E. SELECT Name AS 'Customers/Name', Country AS 'Customers/Country',
OrderId,OrderDate, AmountFROM OrdersINNER JOIN Customers ON Orders.CustomerId
= Customers.CustomerIdWHERE Customers.CustomerId = 1FOR XML PATH
('Customers')
F. SELECT Name, Country, Crderld, OrderDate, AmountFROM OrdersINNER JOIN CustomersON Orders.CustomerId = Customers.CustomerIdWHERE Customers.CustomerId =FOR XML AUTO, ELEMENTS
G. SELECT OrderId, OrderDate, Amount, Name, CountryFROM OrdersINNER JOIN CustomersON Orders.CustomerId = Customers.CustomerIdWHERE Customers.CustomerId = 1FOR XML RAW, ELEMENTS
H. SELECT Name AS '@Name', Country AS '@Country', OrderId, OrderDate,
AmountFROM OrdersINNER JOIN Customers ON Orders.CustomerId
Customers.CustomerIdWHERE Customers.CustomerId = 1FOR XML PATH ('Customers')
Answer: A

NEW QUESTION: 3
Given:
10.class Line {
11.public static class Point {}
12.}
13.14.
class Triangle {
15.// insert code here
16.}
Which code, inserted at line 15, creates an instance of the Point class defined in Line?
A. The Point class cannot be instatiated at line 15.
B. Line l = new Line() ; l.Point p = new l.Point();
C. Point p = new Point();
D. Line.Point p = new Line.Point();
Answer: D