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NEW QUESTION: 1
How can you provide updates to multiple Steelhead Mobile clients at the same time? (Select 2)
A. Using Group IDs
B. Using policies
C. Using profiles
D. Using multiple Steelhead Mobile Controllers
Answer: A,B

NEW QUESTION: 2
You are designing a table for a SQL Server database. The table uses horizontal partitioning.
You have the following requirements:

You need to choose the appropriate data type for the key value.
What should you do?
A. Generate a random value that uses the char(16) data type.
B. Generate a random value that uses the bigint datatype.
C. Use the NEWID function to create a unique identifier.
D. Use the NEWSEQUENTIALID function to create a unique identifier.
Answer: D
Explanation:
Horizontal partitioning divides a table into multiple tables. Each table then contains the same number of columns, but fewer rows. For example, a table that contains 1 billion rows could be partitioned horizontally into 12 tables, with each smaller table representing one month of data for a specific year. Any queries requiring data for a specific month only reference the appropriate table.
NEWSEQUENTIALID creates a GUID that is greater than any GUID previously generated by this function on a specified computer since Windows was started. After restarting Windows, the GUID can start again from a lower range, but is still globally unique. When a GUID column is used as a row identifier, using NEWSEQUENTIALID can be faster than using the NEWID function. This is because the NEWID function causes random activity and uses fewer cached data pages. Using NEWSEQUENTIALID also helps to completely fill the data and index pages.
References:https://msdn.microsoft.com/en-us/library/ms189786.aspx

NEW QUESTION: 3
Consider the following relation definitions:
STUDENT(
Student_Number: integer NOT NULL
Name: variable length character string length 20)
Primary Key Student_Number
HOUSING(
Housing_ID: integer NOT NULL
Student_Number: integer NOT NULL
Building: variable length character string length 25)
Primary Key Housing_ID
Foreign Key Student_Number References STUDENT(Student_Number)
ON DELETE NO ACTION
ON UPDATE CASCADE
What are the referential constraints for the relations defined in these relation definitions?
A. There is no relationship between changes in STUDENT(Student_Number) and HOUSING (Student_Number).
B. Modifications to STUDENT(Student_Number) are automatically reflected in changes to HOUSING (Student_Number). For a deletion to occur from STUDENT(Student_Number), it must first occur in HOUSING(Student_Number).
C. When STUDENT(Student_Number) is changed or deleted, this modification or deletion will automatically be reflected in HOUSING(Student_Number).
D. Modifications to HOUSING(Student_Number) are automatically reflected in changes to STUDENT (Student_Number), but deletions are not permitted.
Answer: B