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NEW QUESTION: 1
In welcher ITIL-Kernveröffentlichung finden Sie detaillierte Beschreibungen des Servicekatalogmanagements, des Informationssicherheitsmanagements und des Lieferantenmanagements?
A. Service-Design
B. Servicestrategie
C. Serviceübergang
D. Servicebetrieb
Answer: A

NEW QUESTION: 2
SHIPMENTSテーブルの構造を調べます。

SHIPMENT_DATEがPO_DATEから1か月より後の場合、PO_IDと支払われるペナルティ額を表示するレポートを生成します。ペナルティは1日あたり20ドルです。
次の2つのクエリを評価します。

上記のコマンドに関して正しい説明はどれですか。
A. 2番目のクエリのみが正常に実行され、正しい結果が得られます。
B. 両方とも正常に実行され、正しい結果が得られます。
C. 最初のクエリのみが正常に実行されますが、誤った結果が返されます。
D. 2番目のクエリのみが正常に実行されますが、誤った結果が返されます。
E. 最初のクエリのみが正常に実行され、正しい結果が得られます。
Answer: E
Explanation:
The MONTHS_BETWEEN(date 1, date 2) function returns the number of months between two dates:
months_between('01-FEB-2008', '01-JAN-2008') = 1
The DECODE Function
Although its name sounds mysterious, this function is straightforward. The DECODE function implements if then-else conditional logic by testing its first two terms for equality and returns the third if they are equal and optionally returns another term if they are not.
DECODE Function Facilitates conditional inquiries by doing the work of a CASE expression or an IF-THENELSE statement:
DECODE(col|expression, search1, result1
[, search2, result2, ..., ]
[, default])
DECODE Function
The DECODE function decodes an expression in a way similar to the IF-THEN-ELSE logic that is used in various languages. The DECODE function decodes expression after comparing it to each search value. If the expression is the same as search, result is returned.
If the default value is omitted, a null value is returned where a search value does not match any of the result values.

NEW QUESTION: 3

A. Option B
B. Option A
C. Option C
D. Option D
Answer: A

NEW QUESTION: 4
Which changes introduced independently will allow code to compile and display 0 1 8 9 (choose all that apply)
#include <iostream>
#include <set>
#include <vector>
using namespace std;
class A {
int a;
public:
A(int a):a(a){}
int getA() const { return a;}
/* Insert Code Here 1 */
};
/* Insert Code Here 2 */
int main(){
A t[] ={ 3, 4, 2, 1, 6, 5, 7, 9, 8, 0 };
vector<A>v(t, t+10);
set<A> s1(v.begin(),v.end());
s1.insert(v.begin(),v.end());
s1.erase(s1.lower_bound(2),s1.upper_bound(7));
for(set<A>::iterator i=s1.begin();i!= s1.end(); i++) {
cout<<i?>getA()<<" ";
}
cout<<endl;
return 0;
}
A. operator int() const { return a;} inserted at Place 1
B. bool operator < (const A & b) const { return b.a<a;} inserted at Place 1
C. bool operator < (const A & a, const A & b) { return a.getA()<b.getA();} inserted at Place 2
D. bool operator < (const A & b) const { return a<b.a;} inserted at Place 1
Answer: A,C,D