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NEW QUESTION: 1
Which three are true regarding purchase order-matched invoices? (Choose three.)
A. You set tolerances to specify the range of variance you will allow if the amounts or quantities on the invoice are less than the amounts or quantities on the purchase order or receipt.
B. You set tolerances to specify the range of variance you will allow if the amounts or quantities on the invoice are greater than the amounts or quantities on the purchase order or receipt.
C. You can set up controls in your system to require you to purchase order-match each invoice.
D. You can set an option on a purchase order shipment that controls whether invoices must match that shipment directly or through a receipt.
E. You can set up controls in your system to require you to invoice-match credit /debit memos that have been matched to a purchase order.
Answer: B,C,D

NEW QUESTION: 2
The economy of Country V is initially in equilibrium at a level of national income and employment denoted by Y, at price level denoted by P If there is an increase in aggregate demand, indicate on the graph below the new equilibrium point in the economy.

Answer:
Explanation:
P2, Y2

NEW QUESTION: 3
You are a database developer for an application hosted on a Microsoft SQL Server 2012 server. The database contains two tables that have the following definitions:

Global customers place orders from several countries. You need to view the country from which each customer has placed the most orders.
Which Transact-SQL query do you use?
A. SELECT c.CustomerID, c.CustomerName, o.ShippingCountryFROM(SELECT c.CustomerID, c.CustomerName, o.ShippingCountry,RANK() OVER (PARTITION BY CustomerIDORDER BY COUNT(o.OrderAmount) ASC) AS RnkFROM Customer cINNER JOIN Orders oON c.CustomerID = o.CustomerIDGROUP BY c.CustomerID, c.CustomerName, o.ShippingCountry) csWHERE Rnk = 1
B. SELECT c.CustomerID, c.CustomerName, o.ShippingCountryFROM Customer cINNER JOIN(SELECT CustomerID, ShippingCountry,COUNT(OrderAmount) DESC) AS OrderAmountFROM OrdersGROUP BY CustomerID, ShippingCountry) AS oON c.CustomerID = o.CustomerIDORDER BY OrderAmount DESC
C. SELECT c.CustomerID, c.CustomerName, o.ShippingCountryFROM Customer cINNER JOIN(SELECT CustomerID, ShippingCountry,RANK() OVER (PARTITION BY CustomerIDORDER BY COUNT(OrderAmount) DESC) AS RnkFROM OrdersGROUP BY CustomerID, ShippingCountry) AS oON c.CustomerID = o.CustomerIDWHERE o.Rnk = 1
D. SELECT c.CustomerID, c.CustomerName, o.ShippingCountryFROM Customer cINNER JOIN(SELECT CustomerID, ShippingCountry,RANK() OVER (PARTITION BY CustomerIDORDER BY OrderAmount DESC) AS RnkFROM OrdersGROUP BY CustomerID, ShippingCountry) AS oON c.CustomerID = o.CustomerIDWHERE o.Rnk = 1
Answer: C


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