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NEW QUESTION: 1

A. Option A
B. Option D
C. Option C
D. Option B
Answer: D

NEW QUESTION: 2
Examine the structure of the EMPLOYEES table. (Choose the best answer.) You must display the details of employees who have manager with MANAGER_ID 100, who were hired in the past 6 months and who have salaries greater than 10000.
A. SELECT last_name, hire_date, salaryFROM employeesWHERE manager_id
(SELECT employee_id FROM employees WHERE employee_id = '100')UNIONSELECT last_name, hire_date, salaryFROM employeesWHERE hire_date > SYSDATE -
180INTERSECTSELECT last_name, hire_date, salaryFROM employeesWHERE salary >
10000;
B. (SELECT last_name, hire_date, salaryFROM employeesWHERE salary > 10000UNION ALLSELECT last_name, hire_date, salaryFROM employeesWHERE manager_ID = (SELECT employee_id FROM employees WHERE employee_id = 100))UNIONSELECT last_name, hire_date, salaryFROM employeesWHERE hire_date > SYSDATE -180;
C. SELECT last_name, hire_date, salaryFROM employeesWHERE manager_id
(SELECT employee_id FROM employees WHERE employee_id = 100)UNION
ALL(SELECT last_name, hire_date, salaryFROM employeesWHERE hire_date >
SYSDATE -180INTERSECTSELECT last_name, hire_date, salaryFROM
employeesWHERE salary > 10000);
D. SELECT last_name, hire_date, salaryFROM employeesWHERE salary > 10000UNION ALL SELECT last_name, hire_date, salaryFROM employeesWHERE manager_ID = (SELECT employee_id FROM employees WHERE employee_id
100)INETRSECTSELECT last_name, hire_date, salaryFROM employees WHERE
hire_date > SYSDATE- 180;
Answer: A

NEW QUESTION: 3



A. Option B
B. Option E
C. Option A
D. Option D
E. Option C
Answer: C