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NEW QUESTION: 1
An architect is helping an organization with the Logical Design of an NSX-T Data Center solution. This information was gathered during the assessment:
* There must be a performance based SLA for East - West traffic.
Which two key performance features should the architect recommend? (Choose two.)
A. Setup RSS to leverage multiple cores.
B. Install advanced Edge pNIC Features.
C. Enable GENEVE-Offload.
D. Configure N-VDS Enhanced Data Path.
E. Leverage DPDK drivers.
Answer: A,C
Explanation:
Explanation
Z -* (D) is wrong because its talking about edge pNIC and the only requirement we have shows performance based SLA for East/West traffic.* ( ) is wrong because DPDK is about edge fast-path for bare-metal NSX-T Edges* (A, B, & C) are all perf enhancers* ( ) is focused on super low latency for NFV type workloads; if its not needed then don't deploy it.* ( ) GENEVE-Offload (TSO for Geneve offload send and LRO for Geneve offload receive) uses Rx/Tx filters for queuing traffic.* ( ) seems like the next best option over (C) as it corresponds to offloading principles of RSS,TSO, & LRO*
https://www.virtualizationhowto.com/2019/10/vmware-nsx-t-performance-tips-and-tuning/

NEW QUESTION: 2
アプリビルダーは、特定のフィールドの集計計算をさまざまなオブジェクトに反映することにより、ユーザーエクスペリエンスを合理化したいと考えています。
これを達成するために、積み上げ集計フィールドで使用する必要がある3つのフィールドタイプはどれですか。
3つの答えを選んでください
A. 日付
B. 時間
C. 通貨
D. パーセント
E. チェックボックス
Answer: D,E

NEW QUESTION: 3
Sie sind Datenbankentwickler einer Microsoft SQL Server 2012-Datenbank.
Sie entwerfen eine Tabelle, in der Kundendaten aus verschiedenen Quellen gespeichert werden. Die Tabelle enthält eine Spalte mit der CustomerID aus dem Quellsystem und eine Spalte mit der SourceID.
Ein Beispiel für diese Daten ist in der folgenden Tabelle aufgeführt.

Sie müssen sicherstellen, dass die Tabelle keine doppelte CustomerID innerhalb einer SourceID enthält. Sie müssen auch sicherstellen, dass die Daten in der Tabelle in der Reihenfolge SourceID und CustomerID vorliegen.
Welche Transact-SQL-Anweisung sollten Sie verwenden?
A. CREATE TABLE Kunde
(SourceID int NICHT NULL PRIMARY KEY CLUSTERED,
CustomerID int NOT NULL UNIQUE,
Kundenname varchar (255) NOT NULL);
B. CREATE TABLE Kunde
(SourceID int NOT NULL IDENTITY,
CustomerID int NOT NULL IDENTITY,
Kundenname varchar (255) NOT NULL);
C. CREATE TABLE Kunde
(SourceID int NOT NULL,
CustomerID int NICHT NULL PRIMARY KEY CLUSTERED,
Kundenname varchar (255) NOT NULL);
D. CREATE TABLE Kunde
(SourceID int NOT NULL,
CustomerID int NOT NULL,
Kundenname varchar (255) NICHT NULL,
CONSTRAINT PK_Customer PRIMARY KEY CLUSTERED
(SourceID, CustomerID));
Answer: D