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NEW QUESTION: 1
A company has complex security requirements. You are asked to set up security access for users.
You need to identify the main attributes for security role, duty, privilege, and permissions.
Which of the following attributes does each of the security components have? To answer, select the appropriate options in the answer area.
NOTE: Each correct selection is worth one point.

Answer:
Explanation:

Explanation

References:
https://docs.microsoft.com/en-us/dynamics365/unified-operations/dev-itpro/sysadmin/role-based-security

NEW QUESTION: 2
Your perimeter Security Gateway's external IP is 200.200.200.3. Your network diagram shows:
Allow only network 192.168.10.0 and 192.168.20.0 to go out to the Internet, using
200.200.200.5.
The local network 192.168.1.0/24 needs to use 200.200.200.3 to go out to the Internet.
Assuming you enable all the settings in the NAT page of Global Properties, how could you achieve these requirements?
A. Create two network objects: 192.168.10.0/24 and 192.168.20.0/24. Add the two network objects to a group object. Create a manual NAT rule like the following: Original source group object; Destination - any; Service - any; Translated source - 200.200.200.5; Destination - original; Service - original.
B. Create a network object 192.168.0.0/16. Enable Hide NAT on the NAT page. Enter
200.200.200.5 as the hiding IP address. Add an ARP entry for 200.200.200.5 for the MAC address of 200.200.200.3.
C. Create an Address Range object, starting from 192.168.10.1 to 192.168.20.254. Enable Hide NAT on the NAT page of the address range object. Enter Hiding IP address
200.200.200.5. Add an ARP entry for 200.200.200.5 for the MAC address of
200.200.200.3.
D. Create network objects for 192.168.10.0/24 and 192.168.20.0/24. Enable Hide NAT on both network objects, using 200.200.200.5 as hiding IP address. Add an ARP entry for
200.200.200.3 for the MAC address of 200.200.200.5.
Answer: C

NEW QUESTION: 3

class Test
int a1;
public static void doProduct(int a) {
a = a * a;
)
public static void doString(StringBuilder s) {
s.append(" " + s);
}
public static void main(String[] args) {
Test item = new Test();
item.a1 = 11;
StringBuilder sb = new StringBuilder("Hello");
Integer i = 10;
doProduct(i);
doString(sb);
doProduct(item.a1);
System.out.println(i + " " + sb + " " + item.a1);
}
}

A. 100 Hello Hello 121
B. 10 Hello Hello 121
C. 10 Hello Hello 11
D. 100 Hello 121
E. 10 Hello 11
Answer: C