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NEW QUESTION: 1
次の中でサーバルームで発生する最も一般的な問題はどれですか？
A. Wet floors
B. Excessive cooling
C. Dust buildup
D. Poor ground wires
Answer: C

NEW QUESTION: 2
You have an Azure subscription named Subscription1.
You plan to deploy an Ubuntu Server virtual machine named VM1 to Subscription1.
You need to perform a custom deployment of the virtual machine. A specific trusted root certification authority (CA) must be added during the deployment.
What should you do? To answer, select the appropriate options in the answer area.
NOTE: Each correct selection is worth one point.

Answer:
Explanation:

References:
https://docs.microsoft.com/en-us/azure/virtual-machines/linux/tutorial-automate-vm-deployment

NEW QUESTION: 3
2番目のフレームリレー仮想回線を受け入れるために、既存のシリアルインターフェイスを設定する必要があります。これを解決するには、次のうちどれが必要ですか？ （3つ選択）
A. interfaceコマンドで仮想インターフェイスを作成します
B. 各サブインターフェイスネットワークの静的フレームリレーマップエントリを設定します。
C. 各サブインターフェイスを独自のIPアドレスで構成します
D. 物理インターフェイスをマルチポイントPPPでカプセル化します
E. 物理インターフェースからIPアドレスを削除します
F. スプリットホライズンを無効にして、サブインターフェイスネットワーク間のルーティングループを防止します
Answer: A,C,E
Explanation:
http://www.orbit-computer-solutions.com/How-To-Configure-Frame-Relay-Subinterfaces.php物理インターフェイスでフレームリレーサブインターフェイスを構成する手順：
1.物理インターフェースに割り当てられているネットワーク層アドレス（IP）を削除します。物理インターフェイスにアドレスがある場合、フレームはローカルサブインターフェイスによって受信されません。
2. encapsulation frame-relayコマンドを使用して、物理インターフェイスでフレームリレーカプセル化を設定します。
3.定義された各PVCに対して、論理サブインターフェイスを作成します。ポート番号を指定し、その後にピリオド（。）とサブインターフェイス番号を指定します。トラブルシューティングを簡単にするために、サブインターフェイス番号がDLCI番号と一致することをお勧めします。
4.インターフェイスのIPアドレスを構成し、帯域幅を設定します。
5. frame-relay interface-dlciコマンドを使用して、サブインターフェイスでローカルDLCIを設定します。
設定例：
R1>enable
R1#configure terminal
R1(config)#interface serial 0/0/0
R1(config-if)#no ip address
R1(config-if)#encapsulation frame-relay
R1(config-if)#no shutdown
R1(config-if)#exit
R1(config-subif)#interface serial 0/0/0.102 point-to-point
R1(config-subif)#ip address 192.168.1.245 255.255.255.252
R1(config-subif)#frame-relay interface-dlci 102
R1(config-subif)#end
R1#copy running-config startup-config

NEW QUESTION: 4
View the Exhibit and examine the data in EMPLOYEES and
DEPARTMENTS tables. In the EMPLOYEES table EMPLOYEE_ID is the PRIMARY KEY and
DEPARTMENT_ID is the FOREIGN KEY. In the DEPARTMENTS table DEPARTMENT_ID is the
PRIMARY KEY.
Evaluate the following UPDATE statement:
UPDATE employees a
SET department_jd =
(SELECT department_id
FROM departments
WHERE location_id = '2100'),
(salary, commission_pct) =
(SELECT 1.1*AVG(salary), 1.5*AVG(commission_pct)
FROM employees b
WHERE a. department_jd = b. department_id)
WHERE first_name|| '||last_name = 'Amit Banda';
What would be the outcome of the above statement?

A. It would not execute successfully because there is no LOCATION_ID 2100 in the DEPARTMENTS table.
B. It would execute successfully and update the relevant data.
C. It would not execute successfully because the condition specified with the concatenation operator is not valid.
D. It would not execute successfully because multiple columns (SALARY,COMMISSION_PCT)cannot be used in an UPDATE statement.
Answer: B