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NEW QUESTION: 1
Ein Unternehmen plant, Microsoft SQL Server auf Linux-basierten Servern auszuführen.
Sie müssen sicherstellen, dass die Einstellungen für die Leistungsoptimierung während der Installation automatisch konfiguriert werden.
Welche Linux-Plattform sollten Sie empfehlen?
A. RHEL
B. SUSE
C. Ubuntu Server
D. Kali Linux
Answer: A
Explanation:
Erläuterung
https://docs.microsoft.com/de-de/sql/linux/sql-server-linux-performance-best-practices?view=sql-server-
2017 # Linux-OS-Konfiguration

NEW QUESTION: 2

A. Option C
B. Option D
C. Option B
D. Option A
Answer: D
Explanation:
*Scenario: Database2 will contain a stored procedure named usp_UpdateInventory. Usp_UpdateInventory will manipulate a table that contains a self-join that has an unlimited number of hierarchies.
*A table variable can be very useful to store temporary data and return the data in the table format. table
*Example: The following example uses a self-join to find the products that are supplied by more than one vendor. Because this query involves a join of the ProductVendor table with itself, the ProductVendor table appears in two roles. To distinguish these roles, you must give the ProductVendor table two different aliases (pv1 and pv2) in the FROM clause. These aliases are used to qualify the column names in the rest of the query. This is an example of the self-join Transact-SQL statement: USE AdventureWorks2008R2; GO SELECT DISTINCT pv1.ProductID, pv1.VendorID FROM Purchasing.ProductVendor pv1 INNER JOIN Purchasing.ProductVendor pv2 ON pv1.ProductID = pv2.ProductID AND pv1.VendorID <> pv2.VendorID ORDER BY pv1.ProductID
Incorrect: Not B: Using a CTE offers the advantages of improved readability and ease in maintenance of complex queries. The query can be divided into separate, simple, logical building blocks. These simple blocks can then be used to build more complex, interim CTEs until the final result set is generated.

NEW QUESTION: 3
どの割り当てが変換エラーにつながりますか？
A. A type C data object with the value '123' to a type C data object with length 2
DATA. gv_c3(3) TYPE c VALUE '123', gv_c2(2) TYPE c. gv_c2 = gv_c3.
B. An XSTRING type data object to a STRING type data object
DATA. gv_xstring TYPE xstring, gv_string TYPE string. gv_xstring = 'AF00'. gv_string =
gv_xstring.
C. A type P data object to a type F data object
DATA. gv_p TYPE p VALUE '15000', gv_f TYPE f. gv_f = gv_p.
D. A type C data object with the value '1.50E4' to a type I data object
DATA. gv_c(6) TYPE c VALUE '1.50E4', gv_i TYPE i. gv_i = gv_c.
Answer: D

NEW QUESTION: 4
For each of the following statements, select Yes if the statement is true. Otherwise, select No. NOTE: Each correct selection is worth one point.

Answer:
Explanation:

Explanation
YES
YES
YES