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12)-2 = 4094

NEW QUESTION: 2
表示ボタンを押して、参照されている「XMLドキュメント」をロードします。
[XMLドキュメント]
<root> <data> lmnop </ data> </ root>
「XMLドキュメント」が「結果XMLドキュメント」に変更されたとします。どのXSLTスタイルシートが正しく変換を実行するかを選択します。
XSLTプロセッサは、変換結果をドキュメントとして出力できることに注意してください。
[結果XMLドキュメント]
<lmnop />
または
<lmnop> </ lmnop>
A. <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:template match= " / " >
<xsl:apply-templates select= " root/data " />
</xsl:template>
<xsl:template match= " data " >
<xsl:element name="{ . }"/>
</xsl:template>
</xsl:stylesheet>
B. <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:template match= " / " >
<xsl:apply-templates select= " root/data " />
</xsl:template>
<xsl:template match= " data " >
<xsl:text disable-output-escaping="no"><</xsl:text>
<xsl:value-of select="."/>
<xsl:text disable-output-escaping="no">/></xsl:text>
</xsl:template>
</xsl:stylesheet>
C. <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:template match= " / " >
<xsl:apply-templates select= " root/data " />
</xsl:template>
<xsl:template match= " data " >
<xsl:element name="."/>
</xsl:template>
</xsl:stylesheet>
D. <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:template match= " / " >
<xsl:apply-templates select= " root/data " />
</xsl:template>
<xsl:template match= " data " >
<xsl:element name="<xsl:value-of select='.'/>"/>
</xsl:template>
</xsl:stylesheet>
Answer: A

NEW QUESTION: 3

A. Option A
B. Option C
C. Option B
D. Option D
Answer: A

NEW QUESTION: 4
From a 1000 ft (305 m) roll of optical fiber, how many MAXIMUM length centralized optical fiber cabling runs can be made?
A. 0
B. 1
C. 2
D. 3
E. 4
Answer: D

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NEW QUESTION: 1
If an Ethernet port on a router was assigned an IP address of 172.16.112.1/20, what is the maximum number of hosts
allowed on this subnet?
A. 0
B. 1
C. 2
D. 3
E. 4
Answer: A
Explanation:
Each octet represents eight bits. The bits, in turn, represent (from left to right): 128, 64, 32 , 16 , 8, 4, 2, 1
Add them up and you get 255. Add one for the all zeros option, and the total is 256.
Now, take away one of these for the network address (all zeros) and another for the broadcast address (all ones). Each
octet represents 254 possible hosts. Or 254 possible networks. Unless you have subnet zero set on your network gear,
in which case you could conceivably have 255.
The CIDR addressing format (/20) tells us that 20 bits are used for the network portion, so the maximum number of
networks are 2