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NEW QUESTION: 1
You are a functional consultant for a company named Contoso Entertainment System USA (USMF).
You need to regenerate a master plan named DynPlan for item number D0023.
To complete this task, sign in to Dynamics 365 portal.
Answer:
Explanation:
See explanation below.
Explanation
You specify the planning method in the dialog box. To open this dialog box, go to Master planning > Master planning in the Master planning workspace.
Regeneration
The regeneration planning method deletes existing planned orders, unless they are firmed. It generates new planned orders, based on all the requirements. Regeneration is the only planning method that is available for static plans.
* Changes in supply are considered. These changes include changes in the forecast.
* This method respects the Period coverage code.
* This method supports product substitution functionality (PI).
Select DynPlan in the Master Plan field.
Select Regeneration in the Planning Method field.
Enter D0023 in the Item Number field.

NEW QUESTION: 2
開発者には、トラフィック状態を取得するためにRESTAPIと統合する仕様があります。このサービスは、パラメーターがフォームエンコードされることを想定しています。
開発者はどのサービスタイプを登録する必要がありますか？
A. HTTPフォーム
B. POSTフォーム
C. HTMLフォーム
D. SOAPフォーム
Answer: A

NEW QUESTION: 3
The RSA Algorithm uses which mathematical concept as the basis of its encryption?
A. Two large prime numbers
B. PI (3.14159...)
C. 16-round ciphers
D. Geometry
Answer: A
Explanation:
Explanation/Reference:
Source: TIPTON, et. al, Official (ISC)2 Guide to the CISSP CBK, 2007 edition, page 254.
And from the RSA web site, http://www.rsa.com/rsalabs/node.asp?id=2214 :
The RSA cryptosystem is a public-key cryptosystem that offers both encryption and digital signatures (authentication). Ronald Rivest, Adi Shamir, and Leonard Adleman developed the RSA system in 1977
[RSA78]; RSA stands for the first letter in each of its inventors' last names.
The RSA algorithm works as follows: take two large primes, p and q, and compute their product n = pq; n is called the modulus. Choose a number, e, less than n and relatively prime to (p-1)(q-1), which means e and (p-1)(q-1) have no common factors except 1. Find another number d such that (ed - 1) is divisible by (p-1)(q-1). The values e and d are called the public and private exponents, respectively. The public key is the pair (n, e); the private key is (n, d). The factors p and q may be destroyed or kept with the private key.
It is currently difficult to obtain the private key d from the public key (n, e). However if one could factor n into p and q, then one could obtain the private key d. Thus the security of the RSA system is based on the assumption that factoring is difficult. The discovery of an easy method of factoring would "break" RSA (see Question 3.1.3 and Question 2.3.3).
Here is how the RSA system can be used for encryption and digital signatures (in practice, the actual use is slightly different; see Questions 3.1.7 and 3.1.8):
Encryption
Suppose Alice wants to send a message m to Bob. Alice creates the ciphertext c by exponentiating: c = me mod n, where e and n are Bob's public key. She sends c to Bob. To decrypt, Bob also exponentiates:
m = cd mod n; the relationship between e and d ensures that Bob correctly recovers m. Since only Bob knows d, only Bob can decrypt this message.
Digital Signature
Suppose Alice wants to send a message m to Bob in such a way that Bob is assured the message is both authentic, has not been tampered with, and from Alice. Alice creates a digital signature s by exponentiating: s = md mod n, where d and n are Alice's private key. She sends m and s to Bob. To verify the signature, Bob exponentiates and checks that the message m is recovered: m = se mod n, where e and n are Alice's public key.
Thus encryption and authentication take place without any sharing of private keys: each person uses only another's public key or their own private key. Anyone can send an encrypted message or verify a signed message, but only someone in possession of the correct private key can decrypt or sign a message.