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NEW QUESTION: 1
Which real time debug should an administrator enable to troubleshoot RADIUS authentication problems?
A. Diagnose authd console -log enable.
B. Diagnose debug application radius -1.
C. Diagnose radius console -log enable.
D. Diagnose debug application fnbamd -1.
Answer: D
Explanation:
https://kb.fortinet.com/kb/documentLink.do?externalID=FD32838

NEW QUESTION: 2
シナリオ：管理者は、既存のXenApp環境に災害復旧機能を追加したいと考えています。管理者は、運用サーバーに1 GBのリンクがある災害復旧データセンターにいくつかの新しいサーバーを構築しました。
管理者はユーザー用に新しいサーバーをどのように構成する必要がありますか？
A. 同じゾーン内の既存のファームにサーバーを追加し、カスタム負荷エバリュエーターを使用します。
B. 同じゾーンの既存のファームにサーバーを追加し、ワーカーグループと負荷分散ポリシーを使用します。
C. サーバーを既存のファームに新しい障害回復ゾーンに追加し、優先的な負荷分散ポリシーを使用します。
D. サーバーを新しいファームに追加し、Web Interfaceのサイトフェイルオーバー機能を使用してサーバーへのアクセスを提供します。
Answer: B

NEW QUESTION: 3
Examine the structure of the EMPLOYEES and DEPARTMENTS tables:

You want to create a report displaying employee last names, department names, and locations. Which query should you use to create an equi-join?
A. SELECT employees.last_name, departments.department_name, departments.location_id FROM employees e, departments D WHERE e.department_id =d.department_id;
B. SELECT e.last_name, d.department_name, d.location_id FROM employees e, departments D WHERE manager_id =manager_id;
C. SELECT e.last_name, d.department_name, d.location_id FROM employees e, departments D WHERE e.department_id =d.department_id;
D. SELECT last_name, department_name, location_id FROM employees , departments ;
Answer: C
Explanation:
Equijoins are also called simple joins or inner joins. Equijoin involve primary key and foreign key.
Incorrect
answer: Athere
is no join Binvalid syntax Cdoes not involve the join in the primary and foreign key
Refer:Introduction toOracle9i:SQL, Oracle University Study Guide, 4-8

NEW QUESTION: 4

A. Option B
B. Option D
C. Option C
D. Option A
Answer: D