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NEW QUESTION: 1
NSR (Non-Stopping-Forwarding) NSR Non-Stopping Routing and non-stop routing (is two solutions for high
reliability)
The following is correct in the case, saying
A. After NSR, , , NR is enabled, if the batch is not yet bundled, the main control board fails and cannot be
completed.
B. NSF NSF routers do not need to communicate with specific vendors.
C. The NSR NSR router needs to communicate with the specific vendor support
D. After the switch is turned on, the router is backed up by NSF GR, and the routing table and table are
kept unchanged. Therefore, the internal traffic does not lose time.
Answer: A,D

NEW QUESTION: 2
eXtreme Programming(XP)チームは、以下を回避するように努めています。
A. Test-Driven Development (TDD).
B. Pair programming.
C. Manual regression testing.
D. Incremental design and architecture.
Answer: C

NEW QUESTION: 3
Health Interfaceのバッチ処理ソリューションとして何をお勧めしますか?
A. Azure Data Factory
B. Azure Databricks
C. Azure Stream Analytics
D. Azure CycleCloud
Answer: C
Explanation:
Explanation
Scenario: ADatum identifies the following requirements for the Health Interface application:
Support a more scalable batch processing solution in Azure.
Reduce the amount of time it takes to add data from new hospitals to Health Interface.
Data Factory integrates with the Azure Cosmos DB bulk executor library to provide the best performance when you write to Azure Cosmos DB.
References:
https://docs.microsoft.com/en-us/azure/data-factory/connector-azure-cosmos-db

NEW QUESTION: 4



A. CREATE TABLE Customer (SourceID int NOT NULL IDENTITY, CustomerID int NOT NULL IDENTITY, CustomerName varchar(255) NOT NULL);
B. CREATE TABLE Customer
(SourceID int NOT NULL,
CustomerID int NOT NULL,
CustomerName varchar(255) NOT NULL,
CONSTRAINT PK_Customer PRIMARY KEY CLUSTERED
(SourceID, CustomerID));
C. CREATE TABLE Customer
(SourceID int NOT NULL,
CustomerID int NOT NULL PRIMARY KEY CLUSTERED,
CustomerName varchar(255) NOT NULL);
D. CREATE TABLE Customer
(SourceID int NOT NULL PRIMARY KEY CLUSTERED,
CustomerID int NOT NULL UNIQUE,
CustomerName varchar(255) NOT NULL);
Answer: B


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