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NEW QUESTION: 1
Sie müssen eine Abfrage erstellen, die die folgenden Anforderungen erfüllt:
* Die Abfrage muss eine Liste von Verkäufern zurückgeben, die nach Umsatzmenge geordnet und nach Postleitzahl geordnet sind.
* Der Verkäufer mit dem höchsten Umsatz muss an erster Stelle stehen.
Ein Teil des korrekten Transact-SQL wurde im Antwortbereich unten bereitgestellt. Geben Sie den Code in den Antwortbereich ein, der das Problem löst und die angegebenen Ziele oder Anforderungen erfüllt. Sie können Code innerhalb des bereitgestellten Codes sowie darunter hinzufügen.


Verwenden Sie die Schaltfläche 'Syntax prüfen', um Ihre Arbeit zu überprüfen. Alle Syntax- oder Rechtschreibfehler werden nach Zeilen- und Zeichenposition gemeldet.
A. 1 SELECT RowNumber () OVER (PARTITION BY PostalCode ORDER BY SalesYTd DESC) AS "Ranking",
2 p.LastName, s.SalesYTD, a.PostalCode
3 FROM Sales.SalesPerson AS a
etc
Fügen Sie in Zeile 1 Folgendes hinzu: RowNumber
Eine Zeile 1 hinzufügen: PARTITION BY
ROW_NUMBER () nummeriert die Ausgabe einer Ergebnismenge. Gibt insbesondere die fortlaufende Nummer einer Zeile innerhalb einer Partition einer Ergebnismenge zurück, beginnend bei 1 für die erste Zeile in jeder Partition.
SYNTAX für ÜBER:
ÜBER (
[<PARTITION BY-Klausel>]
[<ORDER BY-Klausel>]
[<ROW- oder RANGE-Klausel>]
)
Beispiel: Verwenden der OVER-Klausel mit der Funktion ROW_NUMBER
Im folgenden Beispiel wird die ROW_NUMBER für Vertriebsmitarbeiter basierend auf dem zugewiesenen Vertriebskontingent zurückgegeben.
SELECT ROW_NUMBER () OVER (ORDER BY SUM (SalesAmountQuota) DESC) AS RowNumber, Vorname, Nachname, CONVERT (varchar (13), SUMME (SalesAmountQuota), 1) AS SalesQuota FROM dbo.DimEmployee AS e INNER JOIN dbo.Fact ON e.EmployeeKey = sq.EmployeeKey WHERE e.SalesPersonFlag = 1 GROUP BY LastName, FirstName; Hier ist eine Teilergebnismenge.
Zeilennummer Vorname Nachname SalesQuota
--------- --------- ------------------ -------------
1 Jillian Carson 12.198.000,00
2 Linda Mitchell 11.786.000,00
3 Michael Blythe 11.162.000,00
4 Jae Pak 10.514.000,00
B. 1 SELECT RowNumber () OVER (PARTITION BY PostalCode ORDER BY SalesYTd DESC) AS "Ranking",
2 p.LastName, s.SalesYTD, a.PostalCode
3 FROM Sales.SalesPerson AS a
etc
Gibt insbesondere die fortlaufende Nummer einer Zeile innerhalb einer Partition einer Ergebnismenge zurück, beginnend bei 1 für die erste Zeile in jeder Partition.
SYNTAX für ÜBER:
ÜBER (
[<PARTITION BY-Klausel>]
[<ORDER BY-Klausel>]
[<ROW- oder RANGE-Klausel>]
)
Beispiel: Verwenden der OVER-Klausel mit der Funktion ROW_NUMBER
Im folgenden Beispiel wird die ROW_NUMBER für Vertriebsmitarbeiter basierend auf dem zugewiesenen Vertriebskontingent zurückgegeben.
SELECT ROW_NUMBER () OVER (ORDER BY SUM (SalesAmountQuota) DESC) AS RowNumber, Vorname, Nachname, CONVERT (varchar (13), SUMME (SalesAmountQuota), 1) AS SalesQuota FROM dbo.DimEmployee AS e INNER JOIN dbo.Fact ON e.EmployeeKey = sq.EmployeeKey WHERE e.SalesPersonFlag = 1 GROUP BY LastName, FirstName; Hier ist eine Teilergebnismenge.
Zeilennummer Vorname Nachname SalesQuota
--------- --------- ------------------ -------------
1 Jillian Carson 12.198.000,00
2 Linda Mitchell 11.786.000,00
3 Michael Blythe 11.162.000,00
4 Jae Pak 10.514.000,00
Answer: A
Explanation:
References:
https://docs.microsoft.com/en-us/sql/t-sql/functions/row-number-transact-sql
https://docs.microsoft.com/en-us/sql/t-sql/queries/select-over-clause-transact-sql

NEW QUESTION: 2
From the variance F-test shown above, which of these conclusions is/are valid?

A. The variance between the class score distribution is not significantly different
B. There are not enough data points to make any statistical conclusions
C. This test applies only to Normal Distributed data at 99 % confidence
D. The variance between the class score distribution is significantly different
Answer: D

NEW QUESTION: 3
HOTSPOT


Answer:
Explanation: