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NEW QUESTION: 1
Your router is configured to peer with your ISP's router using BGP. You can only control your BGP configuration.

Which address families are negotiated between the two BGP peers shown in the exhibit?
A. inet-unicast inet-vpn-unicast 12vpn
B. inet-vpn-unicast
C. inet-unicast inet-vpn-unicast 12vpn-signaling
D. inet-unicast
Answer: D

NEW QUESTION: 2
A Security team is concerned that a Developer can unintentionally attach an Elastic IP address to an Amazon EC2 instance in production. No Developer should be allowed to attach an Elastic IP address to an instance.
The Security team must be notified if any production server has an Elastic IP address at any time.
How can this task be automated?
A. Use Amazon Athena to query AWS CloudTrail logs to check for any associate-address attempts. Create an AWS Lambda function to dissociate the Elastic IP address from the instance, and alert the Security team.
B. Create an AWS Config rule to check that all production instances have the EC2 IAM roles that include deny associate-address permissions. Verify whether there is an Elastic IP address associated with any instance, and alert the Security team if an instance has an Elastic IP address associated with it.
C. Ensure that all IAM groups are associated with Developers do not have associate-address permissions.
Create a scheduled AWS Lambda function to check whether an Elastic IP address is associated with any instance tagged as production, and alert the Security team if an instance has an Elastic IP address associated with it.
D. Attach an IAM policy to the Developer's IAM group to deny associate-address permissions. Create a custom AWS Config rule to check whether an Elastic IP address is associated with any instance tagged as production, and alert the Security team.
Answer: D
Explanation:
Explanation
https://docs.aws.amazon.com/vpc/latest/userguide/vpc-migrate-ipv6.html#vpc-migrate-ipv6-sg-rules

NEW QUESTION: 3
Given:
class Mid {
public int findMid(int n1, int n2) {
return (n1 + n2) / 2;
}
}
public class Calc extends Mid {
public static void main(String[] args) {
int n1 = 22, n2 = 2;
// insert code here
System.out.print(n3);
}
}

A. Mid m1 = new Calc(); int n3 = m1.findMid(n1, n2);
B. Calc c = new Calc(); int n3 = c.findMid(n1,n2);
C. Calc c = new Mid(); int n3 = c.findMid(n1, n2);
D. int n3 = Calc.findMid(n1, n2);
E. int n3 = super.findMid(n1,n3);
Answer: A,B