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NEW QUESTION: 1
What is one characteristic that indicates that you could have a good opportunity to sell HPE Nimble?
A. The customer is primarily concerned about avoiding and disruption to mission critical services.
B. The customer needs an easier way to migrate data between on-prem and the public cloud.
C. The customer is looking for storage nodes for an object storage solution.
D. The customer has a VMware environment and wants to migrate that to a hyperconverged solution.
Answer: A

NEW QUESTION: 2
Hinweis: Diese Frage ist Teil einer Reihe von Fragen, bei denen die gleichen oder ähnliche Antwortmöglichkeiten verwendet werden. Eine Antwortauswahl kann für mehr als eine Frage in der Reihe richtig sein. Jede Frage ist unabhängig von den anderen Fragen in dieser Reihe. In einer Frage angegebene Informationen und Details gelten für diese Frage.
Sie haben eine Datenbank für ein Bankensystem. Die Datenbank enthält zwei Tabellen mit den Namen tblDepositAcct und tblLoanAcct, in denen Einlagen- und Darlehenskonten gespeichert sind. Beide Tabellen enthalten die folgenden Spalten:

Sie müssen eine Abfrage ausführen, um die Gesamtzahl der Kunden zu ermitteln, die sowohl Einzahlungs- als auch Darlehenskonten haben.
Welche Transact-SQL-Anweisung sollten Sie ausführen?
A. SELECT COUNT (*) FROM (SELECT CustNoFROM tblDepositAcctUNIONSELECT CustNoFROM tblLoanAcct) R
B. SELECT COUNT (DISTINCT D.CustNo) FROM tblDepositAcct D, tblLoanAcct LWHERE D.CustNo = L.CustNo
C. SELECT COUNT (DISTINCT COALESCE (D.CustNo, L.CustNo)) FROM tblDepositAcct DFULL JOIN tblLoanAcct L ON D.CustNo = L.CustNoWhere
D. SELECT COUNT (*) FROM (SELECT AcctNoFROM tblDepositAcctINTERSECTSELECT AcctNoFROM tblLoanAcct) R
E. SELECT COUNT (DISTINCT L.CustNo) VON tblDepositAcct DRIGHT JOIN tblLoanAcct L ON D.CustNo = L.CustNoWHERE D.CustNo IS NULL
F. SELECT COUNT (*) FROM tblDepositAcct DFULL JOIN tblLoanAcct L ON D.CustNo = L.CustNo
G. SELECT COUNT (*) FROM (SELECT CustNoFROM tblDepositAcctUNION ALLSELECT CustNoFROM tblLoanAcct) R
H. SELECT COUNT (*) FROM (SELECT CustNoFROM tblDepositAcctEXCEPTSELECT CustNoFROM tblLoanAcct) R
Answer: D
Explanation:
Explanation
The SQL INTERSECT operator is used to return the results of 2 or more SELECT statements. However, it only returns the rows selected by all queries or data sets. If a record exists in one query and not in the other, it will be omitted from the INTERSECT results.
References: https://www.techonthenet.com/sql/intersect.php

NEW QUESTION: 3
You set up a SnapMirror relationship between two clusters and start the SnapMirror initialization. The transfer starts without error and begins replicating data. Before the initialization completes, a network failure occurs and the transfer fails to finish. Once the network failure is corrected, you attempt to initialize the transfer again, but receive the following error:
Volume rep_vol01 is restricted
Which step should you perform before attempting re-initialization?
A. Change the state of the destination volume to online.
B. Change the state of the destination volume to offline.
C. Delete all data in the destination volume.
D. Delete all Snapshot copies on the destination volume.
Answer: A