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NEW QUESTION: 1
EDI 송장 지불을 승인하기 전에 컴퓨터는 자동으로 송장을 구매 주문서 및 수신 보고서 데이터와 비교합니다. 시스템이 개발 될 때, 감사인은 지불 승인 프로그램을 검토하고 권장 사항을 작성했습니다. 송장 수량이 수령 된 수량보다 많은 상황에 대해 감사자가 가장 권장 한 것은?
A. 청구 금액을 지불하고 차이에 대한 재고를 조정하십시오.
B. 송장을 공급 업체에 반환합니다.
C. 전체 송장 지불을 승인하지만 누락 된 제품에 대해서는 미결 구매 주문 레코드를 유지하십시오.
D. 예외 보고서를 준비하십시오.
Answer: D
Explanation:
An exception report error listing) should be issued so that company personnel can investigate the discrepancy, determine its cause, and take appropriate corrective action.

NEW QUESTION: 2
In the following SQL statement, what is the criteria used for partitioning?

A. none
B. yellow_pages
C. pXX
D. cell_id
E. MAXVALUE
Answer: D
Explanation:
Range Partitioning in Oracle
How does Oracle know how to decompose the single logical table into multiple smaller tables? The answer to this fundamental question is that the user or DBA establishes the criterion used by the database for partitioning. In the case of range partitioning, a partition key is specified. The partition key is based on one or more columns in the table that are associated with a value or range of values. Oracle uses the partition key to decide which partition (smaller table) to put each row in. For example, if the partition key is a date field, then Oracle will look at the date associated with the partition key, and insert that row into the smaller table that contains the range of dates associated with the given date.
For instance, given this table:
CREATE TABLE partn_table (in_date DATE, geom SDO_GEOMETRY)
PARTITION BY RANGE (in_date)
(PARTITION Q1_2004 VALUES LESS THAN ('01-APR-2004'),
PARTITION Q2_2004 VALUES LESS THAN ('01-JUL-2004'),
PARTITION Q3_2004 VALUES LESS THAN ('01-OCT-2004'),
PARTITION Q4_2004 VALUES LESS THAN ('01-JAN-2005')
);
The data is loaded as follows:

References:http://download.oracle.com/otndocs/products/spatial/pdf/spatial_wp10_bestpra c.pdf, page 3

NEW QUESTION: 3
Which of the following stanzas is a valid client configuration for FreeRADIUS?
A. client private-network-1 { ip = 192 0.2.0/24 secret = testingl23-1 }
B. client private-network-1 { ip= 192.0.2.0/24 password-testing123-1 }
C. client private-network-1 { ip = 192 0 2.0/24 passwd = testing123-1 }
D. client pnvate-network-1 { ipaddr = 192 0 2.0/24 password = testing123-1 }
E. client private-network-1 { ipaddr = 192 0 2.0/24 secret = testing 123-1}
Answer: E