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NEW QUESTION: 1
An administrator deploys a WPA2 Enterprise wireless network with EAP-PEAP-MSCHAPv2. The deployment is successful and company laptops are able to connect automatically with no user intervention. A year later, the company begins to deploy phones with wireless capabilities. Users report that they are receiving a warning when they attempt to connect to the wireless network from their phones. Which of the following is the MOST likely cause of the warning message?
A. The phones do not support WPA2 Enterprise wireless networks
B. The phones' built in web browser is not compatible with the wireless network
C. User certificates were not deployed to the phones
D. Mutual authentication on the phone is not compatible with the wireless network
E. Self-signed certificates were used on the RADIUS servers
Answer: A

NEW QUESTION: 2



A. Option B
B. Option A
C. Option C
D. Option D
Answer: A

NEW QUESTION: 3
A customer is experiencing difficulty understanding VoIP calls when copying large files from a computer to the office server. Which of the following settings should be adjusted to resolve the issue?
A. MAC filtering
B. NAT
C. NIC duplex
D. QoS
Answer: B

NEW QUESTION: 4
Heniser Pet Foods는 X.와 Y의 두 가지 제품을 생산합니다.
제품 X와 Y는 각각 미화 30 달러와 50 달러입니다. 각 제품은 재료 A와
B. 제품은 6 파운드의 재료 A와 12 파운드의 재료 B를 사용합니다. 제품 Y는 12 파운드의 재료 A와 8 파운드의 재료 B를 사용합니다. 회사는 1,200 파운드의 재료 A와 1,760 파운드의 재료 B 만 구입할 수 있습니다. 제조 할 제품의 최적 혼합은 다음과 같습니다.
A. 120 단위 및 40 단위 Y.
B. 40 단위의 X 및 120 단위의 Y.
C. 0 단위 X 및 100 단위 Y.
D. 146 단위 및 Y 단위 0 단위.
Answer: A
Explanation:
Linear programming is a technique used to maximize a contribution margin function or to minimize a cost function, subject to constraints such as scarce resources or minimum/maximum levels of production. Thus, linear programming is often used for planning resource allocations. In this problem, the equation to be maximized, called the objective function, is: U3 $30)K+ $50Y. This equation is to be maximized subject to the constraints on materials. The two constraint functions are:
Material A: 6X + 12Y < 1,200 Material B: I 2X + 8Y < 1,760
One way to solve this problem is to graph the constraint lines and determine the feasible area. The optimal production level is at an extreme point within the feasible area. The graph shows that a production level of 120 units of and 40 units of Y is a feasible production level that maximizes the contribution margin.