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NEW QUESTION: 1
You are designing a form that uses a repeating grid to display office furniture items. Which two data sources can you use as a source for a repeating grid? (Choose two.)
A. A page group property that holds the data
B. Local data storage
C. A single value property that contains the data in a local list
D. A page list property that holds the data
Answer: A,D
Explanation:
Explanation/Reference:
Explanation:

NEW QUESTION: 2

A. SAP CRM
B. SAP Business One
C. SAP Business All-In-One
D. SAP ERP
Answer: B

NEW QUESTION: 3
Which of the following provides high availability? (Select TWO).
A. Multipath
B. Hot spare
C. Snapshot
D. Zoneset
E. RAID0
Answer: A,B

NEW QUESTION: 4
You are a database developer for an application hosted on a Microsoft SQL Server 2014 server. The database contains two tables that have the following definitions:

Global customers place orders from several countries. You need to view the country from which each customer has placed the most orders.
Which Transact-SQL query do you use?
A. SELECT c.CustomerID, c.CustomerName, o.ShippingCountry FROM Customer cINNER JOIN(SELECT CustomerID, ShippingCountry,RANK() OVER (PARTITION BY CustomerIDORDER BY OrderAmount DESC) AS RnkFROM OrdersGROUP BY CustomerID, ShippingCountry) AS oON c.CustomerID = o.CustomerIDWHERE o.Rnk = 1
B. SELECT c.CustomerID, c.CustomerName, o.ShippingCountry FROM Customer cINNER JOIN(SELECT CustomerID, ShippingCountry,RANK() OVER (PARTITION BY CustomerIDORDER BY COUNT(OrderAmount) DESC) AS RnkFROM OrdersGROUP BY CustomerID, ShippingCountry) AS oON c.CustomerID = o.CustomerIDWHERE o.Rnk = 1
C. SELECT c.CustomerID, c.CustomerName, o.ShippingCountry FROM Customer cINNER JOIN(SELECT CustomerID, ShippingCountry,COUNT(OrderAmount) DESC) AS OrderAmountFROM OrdersGROUP BY CustomerID, ShippingCountry) AS oON c.CustomerID = o.CustomerIDORDER BY OrderAmount DESC
D. SELECT c.CustomerID, c.CustomerName, o.ShippingCountry FROM(SELECT c.CustomerID, c.CustomerName, o.ShippingCountry, RANK()OVER (PARTITION BY CustomerIDORDER BY COUNT(o.OrderAmount) ASC) AS RnkFROM Customer cINNER JOIN Orders oON c.CustomerID = o.CustomerIDGROUP BY c.CustomerID, c.CustomerName, o.ShippingCountry) cs WHERE Rnk = 1
Answer: B
Explanation:
Use descending (DESC) ordering.
To order by the number of orders we use ORDER BY COUNT(OrderAmount).
Finally a WHERE close is needed: WHERE o.Rnk = 1